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3 years ago

How do you find the slope of the line passing through each pair of points (-4, 19), (4, 9)

Mathematics

1 answer:

qwelly [4]3 years ago

3 0

Answer:

$m=\frac{7}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Point (-4, 19)

Point (4, 9)

Step 2: Find slope m

Substitute: $m=\frac{9+19}{4+4}$
Add: $m=\frac{28}{8}$
Simplify: $m=\frac{7}{2}$

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3 years ago

Please help, photo attached.

steposvetlana [31]

The zeroes of the polynomial functions are as follows:

For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2
For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1
For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1

<h3>What are the zeroes of a polynomial?</h3>

The zeroes of a polynomial are the vales of the variable which makes the value of the polynomial to be zero.

The polynomials are given as follows:

f(x) = 2x(x - 3)(2 - x)

f(x) = 2(x - 3)²(x + 3)(x + 1)

f(x) = x³(x + 2)(x - 1)

For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2

For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1

For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1

In conclusion, the zeroes of a polynomial will make the value of the polynomial function to be zero.

Learn more about polynomials at: brainly.com/question/2833285

#SPJ1

5 0

2 years ago

Bart uses 3/12 cup milk to make muffin. Write a fraction that is equivalent to 3/12

vichka [17]

Your fraction that is equal to 3/12 is 1/4

8 0

3 years ago

Thank you for anyone who knows this

katen-ka-za [31]

Answer:

Part (a) Vertex = (-3, -1)
Part (b) Vertex = (4, 5)
Part (c) function 2; max value = 5

=====================================================

Explanations:

Part (a)

In this case, the vertex is the highest point, so the vertex of function 1 is (-3, -1)

If the parabola was flipped so that it opened upward, instead of downward, then the vertex would be the lowest point.

----------------------------

Part (b)

We could graph this function to see where the highest or lowest point is, but there's another way we could find the vertex using algebra.

The given equation is in the form y = ax^2 + bx + c where in this case

a = -2
b = 16
c = -27

The a and b values are plugged into the formula below to get

h = -b/(2a)

h = -16/(2*(-2))

h = -16/(-4)

h = 4

This is the x coordinate the vertex since the vertex is (h,k)

To find k, we plug that value of h into the original function to find its corresponding y value.

y = -2x^2 + 16x - 27

y = -2(4)^2 + 16(4) - 27

y = -2(16) + 16(4) - 27

y = -32 + 64 - 27

y = 5

We found that h = 4 leads to k = 5. The vertex is (h,k) = (4, 5)

----------------------------

Part (c)

We'll compare the y values of each vertex

Function 1 has a vertex of (-3, 1)
Function 2 has a vertex of (4, 5)

The vertex with the larger y value is the winner, so that would be function 2. This parabola reaches a higher peak compared to the other curve.

The max value here is y = 5. In other words, it's the maximum output the function can produce.

If you graphed functions 1 and 2 together on the same xy grid (see below), you'll see that the curve for function 2 reaches a higher peak.

7 0

3 years ago