The characteristics described in the scatterplot are B. positive correlation D. weak association E. linear.
<h3>What are the condition for Correlation?</h3>
1. Negative Correlation:
The correlation is achieved when either or both values of x and y on the graph decrease.
2. Positive Correlation
The correlation is achieved when the slope (value) of both x and y increases.
3. Strong Correlation
This is achieved when there's uniformity in slopes x and y.
4. Weak Correlation
This is achieved when there are no uniforms in slopes x and y
5. Linear
Linearity is achieved when the data pattern is linear (straight)
6. Nonlinear
Non-Linearity refers to whether a data pattern is curved.
We can see that the characteristics described in the scatterplot are B. positive correlation D. weak association E. linear.
Learn more about correlation coefficient here:
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44 molars she recieved is the range of mummy’s revived
Answer:
Conjugate radicals.
Step-by-step explanation:
The two roots a+sqrb and a-sqr b are called conjugate radicals.
Answer:
6000.
Step-by-step explanation:
Hundreds digit is 6 so we round up the thousand digit (5) to get 6000.
The length of the KN is 4.4
Step-by-step explanation:
We know from Pythagoras theorem
In a right angle ΔLMN
Base² + perpendicular² = hypotenuse
²
From the properties of triangle we also know that altitudes are ⊥ on the sides they fall.
Hence ∠LKM = ∠NKM = 90
°
Given values-
LM=12
LK=10
Let KN be “s”
⇒LN= LK + KN
⇒LN= 10+x eq 1
Coming to the Δ LKM
⇒LK²+MK²= LM²
⇒MK²= 12²-10²
⇒MK²= 44 eq 2
Now in Δ MKN
⇒MK²+ KN²= MN²
⇒44+s²= MN² eq 3
In Δ LMN
⇒LM²+MN²= LN²
Using the values of MN² and LN² from the previous equations
⇒12² + 44+s²= (10+s)
²
⇒144+44+s²= 100+s²+20s
⇒188+s²= 100+s²+20s cancelling the common term “s²”
⇒20s= 188-100
∴ s= 4.4
Hence the value of KN is 4.4
