Answer:
I. L = 10.35 feet
II. W = 93.15 feet.
Step-by-step explanation:
Let the length of the rectangle be L.
Let the width of the rectangle be W.
Given the following data;
Perimeter of rectangular field = 1700 feet
Translating the word problem into an algebraic expression, we have;
W = 9L
Mathematically, the formula for the perimeter of a rectangle is;
P = 2(L + W)
A. To write an equation;
X = P = 2(L + W)
B. To find the dimensions of the field;
207 = 2(L + 9L)
207 = 2L + 18L
207 = 20L
L = 207/20
L = 10.35 feet
To find the weight;
W = 9L
W = 9 * 10.35
W = 93.15 feet.
Therefore, the width of the field is
93.15 feet and the length of the field is
10.35 feet.
Answer:
There were 16 ounces of Cat Food after 24 days.
Step-by-step explanation:
From the graph attached,
For an ordered pair (x, y) lying on the graph,
x-coordinate represents the number of days since bag was bought and y- coordinate represents the ounces of cat food required.
Now the value x = 24 on x-axis shows the number of days since the bag was bought.
For x = 24, ounces of cat food in the bag ( y ) = 16 ounce
Therefore, 16 ounces of Cat Food were in the bag after 24 days since it was bought.
Answer:
The total numbers of possible combinations are 3430.
Step-by-step explanation:
Consider the provided information.
A combination for 0 1 2 3 4 6 5 7 8 9 this padlock is four digits long. Because of the internal mechanics of the lock, no pair of consecutive numbers in the combination can be the same or one place apart on the face.
Here, for the first digit we have 10 choices.
For the second digit we have 7 choices, as the digit can't be the same nor adjacent to the first digit.
For the third digit we have 7 choices, as the digit can't be the same nor adjacent to the second digit.
For the fourth digit we have 7 choices, as the digit can't be the same nor adjacent to the third digit.
So the number of choices are:
![10\times 7\times 7\times 7=10\times 7^3\\10\times 343=3430](https://tex.z-dn.net/?f=10%5Ctimes%207%5Ctimes%207%5Ctimes%207%3D10%5Ctimes%207%5E3%5C%5C10%5Ctimes%20343%3D3430)
Hence, the total numbers of possible combinations are 3430.