Question

Find the value of n such that x2 – 10x + n is a perfect square trinomial.

Answer 1

In a perfect square trinomial , the terms are in the form of

$a^2 + 2ab + b^2$ , so that it can be factored and we get $(a+b)^2$

Now lets compare the given expression

$x^2 - 10x + n$

Now we can compare this with $a^2 + 2ab + b^2$

we get a=x , 2ab = -10x

So we get

2(x) b = -10x

it means 2b = -10

b=-5

But $n=b^2 = (-5)^2 = 25$

Hence, n= 25

Answer 2

value of n such that x2 – 10x + n is a perfect square trinomial. 
ANSWER: 25