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zzz [600]
3 years ago
6

Find the value of n such that x2 – 10x + n is a perfect square trinomial.

Mathematics
2 answers:
Law Incorporation [45]3 years ago
5 0

In a perfect square trinomial , the terms are in the form of


a^2 + 2ab  + b^2 , so that it can be factored and we get (a+b)^2


Now lets compare the given expression

x^2 - 10x + n

Now we can compare this with a^2 + 2ab  + b^2

we get a=x , 2ab = -10x

So we get

2(x) b = -10x

it means 2b = -10

b=-5


But n=b^2 = (-5)^2 = 25


Hence, n= 25

amid [387]3 years ago
3 0
<span>value of n such that x2 – 10x + n is a perfect square trinomial. 
ANSWER: 25</span>
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Answer:

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Step-by-step explanation:

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S_{\Delta ABC}  = 4 ×  S_{\Delta EDC}.

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