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balandron [24]
2 years ago
7

Triangle DEF is translated five units up. If point D has coordinates (-3, -5) what are the coordinates of D'?

Mathematics
1 answer:
Zinaida [17]2 years ago
3 0

Answer:

A

Step-by-step explanation:

A translation of 5 units up means adding 5 to the y- coordinate

Then

D (- 3, - 5 ) → D' (- 3, - 5 + 5 ) → D' (- 3, 0 ) → A

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Find the value of cos P rounded to the nearest hundredth, if necessary.
Lemur [1.5K]

Answer:

\cos P\approx 0.26

Step-by-step explanation:

In any right triangle, the cosine of an angle is equal to its adjacent side divided by the hypotenuse, or longest side, of the triangle.

In the given triangle, the adjacent side to angle P is marked as \sqrt{7} and the hypotenuse of the triangle is 10. Therefore, we have:

\cos P=\frac{\sqrt{7}}{10},\\\cos P=0.2645751311,\\\cos P \approx \boxed{0.26}

7 0
2 years ago
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Please help me with percents
Marta_Voda [28]
79%. A percentage is a number out of 100. So in fraction form, just put the percent number over 100.

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2 years ago
Two systems of equations are shown below:
Sati [7]
System A:
6x + y = 2
-x - y = -3

System B:
2x - 3y = -10
-x-y = -3

Solve:
System A:
6x + y = 2
y = 2 - 6x
-x - (2-6x) = -3
-x - 2 + 6x = -3
5x = -3 + 2
5x = -1
x = -1/5
y = 2 - 6(-1/5)
y = 2 + 6/5
y = 2 + 1.2
y = 3.2     System A: x = -1/5 or -0.2  ; y = 3 1/5 or 3.2

System B:
2x - 3y = -10
2x = -10 + 3y
x = -5 + 1.5y
-x - y = -3
-(-5 + 1.5y) -y = -3
5 - 1.5y - y = -3
-2.5y = -3 - 5
-2.5y = -8
y = 3.2
x = -5 + 1.5(3.2)
x = -5 + 4.8
x = -0.2   System B: x = -0.2 ; y = 3.2

<span>B) They will have the same solution because the first equations of both the systems have the same graph.</span>

6 0
3 years ago
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Find all solutions ​
Anton [14]

Answer:

The solutions of the equation are 0 , π

Step-by-step explanation:

* Lets revise some trigonometric identities

- sin² Ф + cos² Ф = 1

- tan² Ф + 1 = sec² Ф

* Lets solve the equation

∵ tan² x sec² x + 2 sec² x - tan² x = 2

- Replace sec² x by tan² x + 1 in the equation

∴ tan² x (tan² x + 1) + 2(tan² x + 1) - tan² x = 2

∴ tan^4 x + tan² x + 2 tan² x + 2 - tan² x = 2 ⇒ add the like terms

∴ tan^4 x + 2 tan² x + 2 = 2 ⇒ subtract 2 from both sides

∴ tan^4 x + 2 tan² x = 0

- Factorize the binomial by taking tan² x as a common factor

∴ tan² x (tan² x + 2) = 0

∴ tan² x = 0

<em>OR</em>

∴ tan² x + 2 = 0

∵ 0 ≤ x < 2π

∵ tan² x = 0 ⇒ take √ for both sides

∴ tan x = 0

∵ tan 0 = 0 , tan π = 0

∴ x = 0

∴ x = π

<em>OR</em>

∵ tan² x + 2 = 0 ⇒ subtract 2 from both sides

∴ tan² x = -2 ⇒ no square root for negative value

∴ tan² x = -2 is refused

∴ The solutions of the equation are 0 , π

4 0
3 years ago
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What is the value of q in the equation?<br> A) -10/7<br> B) 10/7<br> C)6<br> D) 10
cricket20 [7]

q=10

Remove the radical by raising each side to the index of the radical

Hope this helps!

6 0
3 years ago
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