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balandron [24]
2 years ago
7

Triangle DEF is translated five units up. If point D has coordinates (-3, -5) what are the coordinates of D'?

Mathematics
1 answer:
Zinaida [17]2 years ago
3 0

Answer:

A

Step-by-step explanation:

A translation of 5 units up means adding 5 to the y- coordinate

Then

D (- 3, - 5 ) → D' (- 3, - 5 + 5 ) → D' (- 3, 0 ) → A

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Nesterboy [21]

Answer:

1. x = 1, -2

2.  no solution

3.  x = 6 -4

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Step-by-step explanation:


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3 years ago
PLEASE ANSWER FAST 11 POINTS TO WHOEVER DOES WILL GET BRAIN LISTED PLEASE ANSWER I NEED THIS ASAP
dmitriy555 [2]

Answer: Yes, Raoul is correct because the initial value, also known as the y-intercept of function A is 0 and function B is 3.

Step-by-step explanation: The initial value is when x=0.

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Write each expression as a multiple power of 10
KatRina [158]

Answer:

ok

Step-by-step explanation:

3 0
3 years ago
A cable television compan is laying cable in an area with underground utilities. Two subdivisions are located on opposite sides
Schach [20]

Answer:

Step-by-step explanation:

Given:

Point Q = Q is on the north bank 1200 m east of P $40/m to lay cable underground and $80/m way to lay the cable.

Lets denote T be a point on north bank, therefore, point T is t m east and 100m north of P.

Note that 0 < t < 1200

Distance from P to T using Pythagoras theorem:

PT^2 = PQ^2 + QT^2

PT = √(t²+100²) = √(t²+10,000)

Distance from T to Q:

TQ = 1200 - t

From above, Cable from P to T is underwater, and costs $80/m to lay.

Cable from T to Q is underground, and costs $40/m to lay.

Total cost of the cable:

C(t) = 80√(t²+10,000) + 40(1200 - t)

Cost is at its minimum: when dC/dt = C'(t) = 0 and d^2C/dt^2 = C''(t) > 0

dC/dt = C'(t)

= 80 * 1/2 (t² + 10,000)^(-1/2) × 2t + 40 × (-1)

dC/dt = C'(t)

= 80t/√(t² + 10,000) - 40 = 0

80t/√(t² + 10,000) = 40

80t = 40√(t² + 10,000)

2t = √(t² + 10,000)

square both sides:

4t² = t² + 10,000

3t² = 10,000

t² = 10,000/3

t = 100/√3

≈ 57.735

d^2C/dt^2 =

C''(t) = [80√(t² + 10,000) - 80t × t/√(t²+10,000)] /√(t²+10,000)

C''(t) = [(80(t²+10,000) - 80t²) / √(t²+10,000)] /√(t²+10,000)

C''(t) = 800,000 / (t² + 10,000)^(3/2)

C''(t) > 0 for all t

Therefore C(t) is minimized at t = 100/√3

C(100/√3) = 80√(10,000/3 + 10,000) + 40 × (1200 - 100/√3)

= 80 √(40,000/3) + 48,000 - 4000/√3

= 16000/√3 + 48,000 - 4000/√3

= 48,000 + 12,000/√3

= 48,000 + 4,000√3

= 4000 (12 + √3)

≈ 54,928.20

Minimum cost is $54,928.20

This occurs when cable is laid underwater from point P to point T(57.735 m east and 100m north of P) and then underground from point T to point Q (1200 - 57.735)

= 1142.265 m

5 0
3 years ago
What is 2x2x2x2+2+2+2divitide by 6
Luba_88 [7]

Answer:

3.6 repeating or 3 and 2/3

Step-by-step explanation:

I did the work on a calculator.

4 0
3 years ago
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