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Crank
3 years ago
7

What set of reflections would carry rectangle ABCD onto itself?

Mathematics
1 answer:
dexar [7]3 years ago
5 0
We are given a quadrilateral in the Cartesian coordinates whose vertex have the following coordinates:
A (-5,1)
B (-5,3)
C (-1,3)
D (-1,1)

For a set of reflection to result in the same image location and size, the image must be rotated 360 degrees. Among the choices, the only answer is
<span>y-axis, x-axis, y-axis, x-axis</span>
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Which equation is the inverse of y=100-x2
postnew [5]

Answer:

f^-1(x)=100-x

Step-by-step explanation:


4 0
3 years ago
Read 2 more answers
Use the cross product property to solve each equation: 5/7 = x/9
enot [183]

Answer:

x = 45/7

Step-by-step explanation:

\frac{5}{7} =\frac{x}{9}

Here, you can more easily see what the fractions look like.

In order to cross-multiply, you have to multiply 5 with 9, and 7 with x.

45 = 7x

Then, you isolate x by dividing 7 on both sides:

45/7 = x

Hope I helped :)

8 0
3 years ago
Need math help. Thanks in advance.
Mademuasel [1]
9. D because it fits the description when it is graphed. 
11. D because it has the correct vertex, which is (1.5, 4.75). 
12. f(x)=-4(x-2)²+16 works with the table and provided graph!
13. 0 isn't a zero for f(x), so B is correct (the zeros are 1/2 and 4). 
14. The width is about 3.831. 
15. The answer is B because the equation for a parabola in this form is: 
      f(x) = (x - r₁)(x - r₂)

Every one of these except for 15 was solved using desmos, a graphing calculator. 

Hope this helps!
7 0
3 years ago
The hypotenuese of an isosceles right triangle is 13 inches. The midpoints of its sides are connected to form an inscribed trian
Georgia [21]

Answer:

The Sum of the areas of theses triangles is 169/3.

Step-by-step explanation:

Consider the provided information.

The hypotenuse of an isosceles right triangle is 13 inches.

Therefore,

x^2+x^2=169\\2x^2=169\\x=\frac{13}{\sqrt{2} }

Then the area of isosceles right triangle will be: A=\frac{1}{2} x^2

Therefore the area is: A=\frac{169}{4}

It is given that sum of the area of these triangles if this process is continued infinitely.

We can find the sum of the area using infinite geometric series formula.

S=\frac{a}{1-r}

Substitute a=\frac{169}{4} \ and\ r=\frac{1}{4} in above formula.

S=\frac{\frac{169}{4}}{1-\frac{1}{4}}

S=\frac{\frac{169}{4}}{\frac{3}{4}}

S=\frac{169}{3}

Hence, the Sum of the areas of theses triangles is 169/3.

7 0
3 years ago
D2-9k+3 for d=10 and k=9
AVprozaik [17]

Answer:

22

Step-by-step explanation:

10^2-9(9)+3

100-81+3

19+3

22

8 0
3 years ago
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