Answer:
(a) Probability that a randomly selected student is taking Spanish given that he or she is taking French = 0.5 .
(b) Probability that a randomly selected student is not taking French given that he or she is not taking Spanish = 0.6 .
Step-by-step explanation:
We are given that an elementary school is offering 2 language classes ;
  <em>Spanish Language is denoted by S and French language is denoted by F.</em>
Also we are given, P(S) = 0.5 {Probability of students taking Spanish language}
 P(F) = 0.4 {Probability of students taking French language}
  = 0.7 {Probability of students taking Spanish or French Language}
 = 0.7 {Probability of students taking Spanish or French Language}
<em>We know that,  </em> <em>  = </em>
<em>  = </em> <em> </em>
<em> </em> <em />
<em />
So,  =
 =  = 0.5 + 0.4 - 0.7 = 0.2
 = 0.5 + 0.4 - 0.7 = 0.2
   means Probability of students taking  both Spanish and French Language.
 means Probability of students taking  both Spanish and French Language.
Also, P(S)' = 1 - P(S) = 1 - 0.5 = 0.5
          P(F)' = 1 - P(F) = 1 - 0.4 = 0.6
          = 1 -
 = 1 -   = 1 - 0.7 = 0.3
 = 1 - 0.7 = 0.3
(a) Probability that a randomly selected student is taking Spanish given that he or she is taking French is given by P(S/F);
   P(S/F) =  =
 =  = 0.5
 = 0.5
(b) Probability that a randomly selected student is not taking French given that he or she is not taking Spanish is given by P(F'/S');
    P(F'/S') =  =
 =  =
 =  = 0.6 .
 = 0.6 .
Note: 2. A pair of fair dice is rolled until a sum of either 5 or 7 appears  ; This question is incomplete please provide with complete detail.