3 years ago

Olk-onm Find the value of u.

1 answer:

5 0

Answer:

olk 69 -_-

Step-by-step explanation:

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Katyanochek1 [597]

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3 years ago

Taya2010 [7]

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$\frac{2x + 4}{2} < 6 \\ 2x + 4 < 2 \times 6 \\ 2x + 4 < 12 \\ 2x < 12 - 4 \\ 2x < 8 \\ x < \frac{8}{2} \\ \color{blue} \boxed{x < 4}$

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3 years ago

drek231 [11]

Hi there!

~

$( 2x + 3y)^2$

$= (2x + 3y) (2x + 3y)\\= (2x)(2x)+ (2x) (3y) + (3y)(2x) +(3y)(3y)\\=4x^2 + 6xy + 6xy + 9y^2\\= 4x^2 + 12xy + 9y^2$

Answer : $4x^2 + 12xy + 9y^2$

Hope this helped you!

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4 years ago