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Number of children attended is 1200 and number of adults attended is 1500
<h3><u>Solution:</u></h3>Given that,
Admission fee for each children = $ 1.50
Admission fee for each adult = $ 4.00
Let "c" be the number of children attended
Let "a" be the number of adults attended
Given that 2700 people enter and $7800 is collected
Number of children attended + number of adults attended = 2700
c + a = 2700 -------- eqn 1
Also given that $7800 is collected
Number of children attended x Admission fee for each children + number of adults attended x Admission fee for each adult = 7800
1.5c + 4a = 7800 -------- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "a" and "c"
From eqn1,
a = 2700 - c ----- eqn 3
Substitute eqn 3 in eqn 2
1.5c + 4(2700 - c) = 7800
1.5c + 10800 - 4c = 7800
-2.5c = -3000
c = 1200
Therefore from eqn 3,
a = 2700 - 1200
a = 1500
Therefore number of children attended = c = 1200
number of adults attended = a = 1500
