1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mamaluj [8]
3 years ago
12

PLLEASEEEE ANSWER HURRY

Mathematics
1 answer:
Galina-37 [17]3 years ago
6 0
The answer is y=-8 I’m pretty sure
You might be interested in
Angelica's biweekly salary is $2240.<br> What is her gross monthly salary?
ArbitrLikvidat [17]

Answer:

Monthly = 4853.33

Bi weekly = $2240

x26 = 58240

/12 =4853.33333333

Monthly = 4853.33

4 0
3 years ago
Find the arc length of the given curve between the specified points. x = y^4/16 + 1/2y^2 from (9/16), 1) to (9/8, 2).
lutik1710 [3]

Answer:

The arc length is \dfrac{21}{16}

Step-by-step explanation:

Given that,

The given curve between the specified points is

x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}

The points from (\dfrac{9}{16},1) to (\dfrac{9}{8},2)

We need to calculate the value of \dfrac{dx}{dy}

Using given equation

x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}

On differentiating w.r.to y

\dfrac{dx}{dy}=\dfrac{d}{dy}(\dfrac{y^2}{16}+\dfrac{1}{2y^2})

\dfrac{dx}{dy}=\dfrac{1}{16}\dfrac{d}{dy}(y^4)+\dfrac{1}{2}\dfrac{d}{dy}(y^{-2})

\dfrac{dx}{dy}=\dfrac{1}{16}(4y^{3})+\dfrac{1}{2}(-2y^{-3})

\dfrac{dx}{dy}=\dfrac{y^3}{4}-y^{-3}

We need to calculate the arc length

Using formula of arc length

L=\int_{a}^{b}{\sqrt{1+(\dfrac{dx}{dy})^2}dy}

Put the value into the formula

L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4}-y^{-3})^2}dy}

L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-2\times\dfrac{y^3}{4}\times y^{-3}}dy}

L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-\dfrac{1}{2}}dy}

L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4})^2+(y^{-3})^2+\dfrac{1}{2}}dy}

L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4}+y^{-3})^2}dy}

L= \int_{1}^{2}{(\dfrac{y^3}{4}+y^{-3})dy}

L=(\dfrac{y^{3+1}}{4\times4}+\dfrac{y^{-3+1}}{-3+1})_{1}^{2}

L=(\dfrac{y^4}{16}+\dfrac{y^{-2}}{-2})_{1}^{2}

Put the limits

L=(\dfrac{2^4}{16}+\dfrac{2^{-2}}{-2}-\dfrac{1^4}{16}-\dfrac{(1)^{-2}}{-2})

L=\dfrac{21}{16}

Hence, The arc length is \dfrac{21}{16}

6 0
3 years ago
What is wrong with this problem. 2(n +3) = 2n +3
LekaFEV [45]

Steps to solve:

2(n + 3) = 2n + 3

~Distribute left side

2n + 6 = 2n + 3

~Subtract 6 to both sides

2n = 2n - 3

~Subtract 2n to both sides

n = -3

Best of Luck!

7 0
3 years ago
Heather buys a dog bowl priced at $8. If the sales tax is 10%, how much tax will Heather<br> pay?
Fantom [35]

Answer:

I think the answer is 2 dollars

Step-by-step explanation:

4 0
3 years ago
"Define a variable write an inequality and solve each problem".A number +1 is greater than -5 less than three.
Brrunno [24]

Answer:  -5 < x + 1 < 3

Step-by-step explanation:

Let x be the number.

-5 < x + 1 < 3

4 0
3 years ago
Other questions:
  • What is the range of the function y= ^3 square root x-5
    11·1 answer
  • Solve fot z show all your work. 7z - 18 =2z+ 18​
    7·1 answer
  • -2y+2=-2(3y+11) how to figure this out
    8·2 answers
  • What is the slope of the line on the graph?
    9·1 answer
  • Question (2)
    5·2 answers
  • Mr. Garcia buy three bags of cat food that each way 9 pounds and another bag of cat food that weighs 7 pounds how many pounds of
    8·1 answer
  • !!!!!!!HELP!!!!!!!
    7·1 answer
  • PLEASE HELP I NEED IT TO PASS THIS CLASS
    11·2 answers
  • What is the Range of the following?<br> (-00,00)<br> (-00,9)<br> [-5,4]<br> [-4.9]
    9·1 answer
  • Evaluate 3x2 - 4 when χ= 2.<br> Α. 2<br> Ο Ο Ο<br> Ο Β. 8<br> C. 12<br> Ο D. 32
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!