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3 years ago

The polynomial 16x +2 is a ? Adding the term ? Would make it a trinomial

Mathematics

2 answers:

trapecia [35]3 years ago

7 0

What are the instructions? If it just says to classify it, there is no degree, so it would be a binomial.

Here is a chart;

1 term = monomial. Example; 6x

2 terms = binomial. Example; 6x + 5

3 terms = Trinomial. Example; 6x + 5 + 2y

4 terms = polynomial of 4 terms. Example; 6x + 5 + 2y + 2x^3

EastWind [94]3 years ago

4 0

Answer:

1. binomal

2. xy

Step-by-step explanation:

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( please help, 20 points!! )

deff fn [24]

Measure of anfle 5=150

7 0

2 years ago

Help!! Answer !!! about to run out of time in test!!

Gemiola [76]

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

$\qquad \sf \dashrightarrow \: h {}^{2} = {8}^{2} + {6}^{2}$

$\qquad \sf \dashrightarrow \: h {}^{2} = {36}^{} + {64}^{}$

$\qquad \sf \dashrightarrow \: h {}^{2} = 100$

$\qquad \sf \dashrightarrow \: h {}^{} = \sqrt{100}$

$\qquad \sf \dashrightarrow \: h {}^{} = {10}$

Now, let's find the asked values ~

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{opposite \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{6}{10}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{3}{5} \: or \: 0.6 \: units$

For Cos y :

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{adjcant \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{6}{10}$

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{3}{5} \: or \: 0.6 \: units$

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

3 0

2 years ago

IMPORTANT IMPORATANT PLZZZ HELPPP

Gekata [30.6K]

Answer:

Step-by-step explanation:

Your answer is the first picture (upper left)

8 0

2 years ago

Find Distance (4,6) (-4,-3)

vampirchik [111]

Answer:

$\sqrt{145}$

Step-by-step explanation:

The distance formula states that the distance between two points $(a,b)$ and $(c,d)$ is $\sqrt{(a-c)^2+(b-d)^2}$ .

The two points we have are $(4,6)$ and $(-4,-3)$ . Plugging these numbers into the distance formula, we have

$\sqrt{(4-(-4))^2+(6-(-3))^2$ .

Simplifying with order of operations, first using the distributive property, gives

$\sqrt{(4+4)^2+(6+3)^2$ .

Squaring and adding gives

$\sqrt{(4+4)^2+(6+3)^2}=\sqrt{8^2+9^2}\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~=\sqrt{64+81}\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~=\boxed{\sqrt{145}},$

which is the answer in simplest form. This also rounds to about 12.04.

7 0

2 years ago

The function f(x)=x^2 is graphed on the coordinate grid.

Aleksandr [31]

<h3>Answer:</h3>

graphed below.

<h3>Explanation:</h3>

vertex: (0, 0)

other points:

-2 12

-1 3

0 0

1 3

2 12

7 0

2 years ago

Read 2 more answers