Can someone help? Solve for x

Math questions..............................

Sergeu [11.5K]

The answer is 490 m2

3 0

3 years ago

Read 2 more answers

A leather ball has a diameter of 28.4 cm. Which is the area of the piece of leather used on the surface of the ball?

Ira Lisetskai [31]

Answer:

$A=806.56\pi\ cm^2$

Step-by-step explanation:

Given that,

The diameter of a leather ball, d = 28.4 cm

Radius, r = 14.2 cm

We need to find the area of the piece of leather used on the surface of the ball. The surface area of the ball is given by :

$A=4\pi r^2\\\\A=4\times \pi\times (14.2)^2\\\\A=806.56\pi\ cm^2$

So, the area of the piece of leather is $806.56\pi\ cm^2$ . The correct option is (b).

7 0

3 years ago

What is the center of a circle with the equation (x - 6)2 + (y + 2)2 = 9?

galina1969 [7]

Answer:

B. (6,-2)

Step-by-step explanation:

The equation of a circle is (x-h)^2+(y-k)^2=r^2

The center of the circle is (h,k)

So, in this problem, h is 6 and k is -2, so the center of this circle is (6,-2).

4 0

4 years ago

Solve. Good luck! Please do not try to google this.

Elena L [17]

$\frac{x^{2} + x - 2}{6x^{2} - 3x} = \sqrt{2x} + \frac{3x^{2}}{2}$
$\frac{x^{2} + 2x - x - 2}{3x(x) - 3x(1)} = \frac{2\sqrt{2x}}{2} + \frac{3x^{2}}{2}$
$\frac{x(x) + x(2) - 1(x) - 1(2)}{3x(x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$\frac{x(x + 2) - 1(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$\frac{(x - 1)(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$\frac{(x - 1)(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$3x(2x - 1)(2\sqrt{2x} + 3x^{2}) = 2(x + 2)(x - 1)$
$3x(2x(2\sqrt{2x} + 3x^{2}) - 1(2\sqrt{2x} + 3x^{2}) = 2(x(x - 1) + 2(x - 1))$
$3x(2x(2\sqrt{2x}) + 2x(3x^{2}) - 1(2\sqrt{2x}) - 1(3x^{2})) = 2(x(x) - x(1) + 2(x) - 2(1)$
$3x(4x\sqrt{2x} + 6x^{3} - 2\sqrt{2x} - 3x^{2}) = 2(x^{2} - x + 2x - 2)$
$3x(4x\sqrt{2x} - 2\sqrt{2x} + 6x^{3} - 3x^{2}) = 2(x^{2} + x - 2)$
$3x(4x\sqrt{2x}) - 3x(2\sqrt{2x}) + 3x(6x^{3}) - 3x(3x^{2}) = 2(x^{2}) + 2(x) - 2(2)$
$12x^{2}\sqrt{2x} - 6x\sqrt{2x} + 18x^{4} - 9x^{3} = 2x^{2} + 2x - 4$
$12x^{2}\sqrt{2x} - 6x\sqrt{2x} = -18x^{4} + 9x^{3} + 2x^{2} + 2x - 4$
$6x\sqrt{2x}(2x) - 6x\sqrt{2x}(1) = -9x^{3}(2x) - 9x^{3}(-1) + 2(x^{2}) + 2(x) - 2(2)$
$6x\sqrt{2x}(2x - 1) = -9x^{3}(2x - 1) + 2(x^{2} + x - 2)$

5 0

4 years ago

Jim deposits 6000 into an account that pays simple interest at a rate of 2% per year. How much interest will he be paid in the f

Alex73 [517]

Answer:

$600 interest will be paid in the first 5 years

Step-by-step explanation:

Simple interest is calculated only on the principal or initial amount deposited. Jim deposits 6000 into an account that pays simple interest at a rate of 2% per year. The formula for simple interest is expressed as

I = PRT/100

Where

I represents interest after the given time.

R represents the interest loan on the principal.

T represent number of time in years.

P represents principal or initial amount deposited.

From the information given,

R = 2

P = 6000

T = 5

I = (6000 × 2 × 5)/100 = $600

6 0

3 years ago