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3 years ago

7

24-5₂ Sorry i tried to put the 2 at the top edge of the 5 but i could not.

1 answer:

Archy [21]3 years ago

5 0

Explanation in this file

\\Workhelp2gow//.com

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Given the points R (6,-2) and T (-9,- 7), find the coordinates of point S on line RT such that the ratio of RS to ST is 3 : 2 p

Sholpan [36]

Answer:

(-3, -5)

Step-by-step explanation:

By using the distance formula, we see that the length of RT is $\sqrt{(6+9)^2+(-2+7)^2}$ which equals $5\sqrt{10}$ .

The ratio of RS to ST is 3:2, so we can write the distance of RS as $(5\sqrt{10} / 5) * 3$ which equals $3\sqrt{10}$ . The distance of ST is then $2\sqrt{10}$ .

Since we know the distance of RS and ST, we can find the coordinates of point S by using the distance formula again:

$\sqrt{(6-x)^2+(-2-y)^2} = 3\sqrt{10}$ and $\sqrt{(-9-x)^2+(-7-y)^2} = 2\sqrt{10}$

We solve for x and y, getting (-3, -5).

3 0

3 years ago

Helena creates two similar rectangles using exactly 100 cm of string. The smaller rectangles width and length are 4 cm by 6 cm r

Misha Larkins [42]

Answer:

The dimensions of the larger rectangle are $24\ cm$ of length by $16\ cm$ of width

Step-by-step explanation:

Let

x-----> the length of the larger rectangle

y-----> the width of the larger rectangle

we know that

$\frac{x}{y}=\frac{6}{4}$ ------> by similar rectangles

$x=1.5y$ -----> equation A

<u>Find the perimeter of the smaller rectangle</u>

$P=2(6+4)=20\ cm$

<u>Find the perimeter of the larger rectangle</u>

Subtract the perimeter of the smaller rectangle from 100 cm of string

$P=100-20=80\ cm$

Remember that

$80=2x+2y$ ------> $40=x+y$ ------> equation B

substitute equation A in equation B

$40=1.5y+y$

$2.5y=40$

$y=16\ cm$

Find the value of x

$x=1.5(16)=24\ cm$

The dimensions of the larger rectangle are $24\ cm$ of length by $16\ cm$ of width

3 0

3 years ago

What is the recursive formula for this geometric sequence?–2, –16, –128, –1024, ...

Tatiana [17]

Answer:

$b_n=-2\cdot 8^{n-1}$

Step-by-step explanation:

Denote first four terms of the geometrc sequence as

$b_1=-2,\\ \\b_2=-16,\\ \\b_3=-128,\\ \\b_4=-1024.$

Note that

$b_2=b_1\cdot q\Rightarrow -16=-2\cdot 8;\\ \\b_3=b_2\cdot q\Rightarrow -128=-16\cdot 8;\\ \\b_4=b_3\cdot q\Rightarrow -1024=-128\cdot 8.$

Then the common ratio is

$q=8.$

Therefore, the recursive formula for the geometric sequence is

$b_n=b_1\cdot q^{n-1}\Roghtarrow b_n=-2\cdot 8^{n-1}.$

5 0

3 years ago

WILL GIVE BRAINLIEST!

zvonat [6]

Answer: c

Step-by-step explanation:

are going to mark me brainly

7 0

3 years ago

Read 2 more answers

(5x^2-8x+1)+(2x^2-4x-11)

UkoKoshka [18]

Answer:

7x^2 - 12x - 10

Step-by-step explanation:

5x^2 - 8x + 1 + (x^2 - 4x - 11)

7x^2 - 8x + 1 - 4x - 11

3 0

3 years ago