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Leona [35]
3 years ago
3

The small intestine couldn't work without the

Biology
2 answers:
belka [17]3 years ago
5 0
The small intestines Couldnt work without the large intestines
LenKa [72]3 years ago
3 0
The small intestine couldn't work without the large intestine
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Which description is an example of converting gravitational energy into kinetic energy?
Troyanec [42]
When an object from a pause state begins to move the potential energy is changed into kinetic energy. One of the example is the yo-yo, it has stored energy due to its position. Once the yo-yo begins its fall the potential energy will change to kinetic energy and vice versa.
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3 years ago
What traits do viruses share with living things?<br>​
Ksivusya [100]

Answer: Viruses are infectious agents with both living and nonliving characteristics. Living characteristics of viruses include the ability to reproduce – but only in living host cells – and the ability to mutate.

Explanation:

googles word not mines, but put it in your own.

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What is potential energy?<br><br><br><br> Read comment at the bottom
photoshop1234 [79]
It’s stored energy yk you could of just looked it up
5 0
3 years ago
Can some help me with #2 and # 3? Please thanks
goldfiish [28.3K]

Answer:

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6 0
4 years ago
Read 2 more answers
Two phenotypically normal parents have a child with CF. i. What are the genotypes of each parent? ii. What is the probability th
katen-ka-za [31]

To first dive into your question, here are some vocabulary terms that I will be using and will be helpful to you as well.

  • Homozygous dominant (BB): <em>Is not affected by cystic fibrosis</em>.
  • Homozygous recessive (bb):<em> Is affected by cystic fibrosis</em>.
  • Heterozygous (Bb):<em> A carrier for cystic fibrosis</em>.
  • Phenotype (Ex: Having cystic fibrosis): <em>The appearance of an allele pair</em>.
  • Genotype (Ex: bb): <em>The genetic makeup of an allele pair</em>.

We know that if both of the parents are phenotypically normal, there is no way that they can be homozygous recessive (bb), or have cystic fibrosis. We also know that since they have a child with this disease, they can't be homozygous dominant (BB) either. This means that <u>both parents have to be carriers (Bb)</u> in order for them to have a child with cystic fibrosis.

Below I have attached a Punnett square with both of the heterozygous parents.

<em>Each child they have will have a </em><u><em>1/4</em></u><em> or </em><u><em>25%</em></u><em> chance of having cystic fibrosis.</em>

5 0
3 years ago
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