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3 years ago

Differentiate among web apps, mobile apps, and mobile web apps.

Computers and Technology

2 answers:

Alchen [17]3 years ago

7 0

web apps are for computers

olchik [2.2K]3 years ago

4 0

Mobile apps vs. web apps. Native mobile apps are built for a specific platform, such as iOS for the Apple iPhone or Android for a Samsung device. They are downloaded and installed via an app store and have access to system resources, such as GPS and the camera function. Mobile apps live and run on the device itself.

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Why is Resnick skeptical of calling the young people of today ‘digital natives’? Do you agree? Explain.

Nezavi [6.7K]

For question one, Resnick skeptical of calling the young people of today 'digital natives' will have to be agree. For agreeable reasons is because people who are called "digital natives", is because they are in a technological state that they are familiar with. Which means that if young people are in a state of technology and they are really into it, you have this unbreakable string tied to the waist and it hangs into you from a tree. And for reason two, is because coding can be helpful. In situations like people hacking you, with coding, now that is when it comes in.

And for the others, I'll have to look at some more information I might have. But, here is your first answer is up above, If it isn't good enough, then let me know.

Hope this helps.

~Karleif

3 0

3 years ago

What are the most common types of Asynchronous communication?

coldgirl [10]

An asynchronous communication service or application does not require a constant bit rate. Examples are file transfer, email and the World Wide Web. An example of the opposite, a synchronous communication service, is realtime streaming media, for example IP telephony, IP-TV and video conferencing.

7 0

3 years ago

Given int variables k and total that have already been declared, use a while loop to compute the sum of the squares of the first

Bumek [7]

Answer:

The c++ program for the given scenario is as follows.

#include <iostream>

using namespace std;

int main() {

int k, total;

k=1;

total=0;

while(k<=50)

{

// square of every counting number is added to total

total = total + (k*k);

// value of k is incremented to move on to the next counting number

k++;

}

cout<<"Sum of squares of first 50 counting numbers is " << total<<endl;

return 0;

}

OUTPUT

Sum of squares of first 50 counting numbers is 42925

Explanation:

As mentioned, only two variables k and total are used in the program. These variables are declared with data type integer.

Variable k is initialized to 1 and variable total is initialized to 0.

k=1;

total=0;

Variable k is used to represent counting number whose square is added to the variable total. Hence, values are taken accordingly.

The while loop is also known as the pre-test loop. This loop first evaluates the given condition and executes if the condition is satisfied.

while(k<=50)

The above while loop will execute till the value of variable k is less than or equal to 50. Once the value of k exceeds 50, the loop gets terminated. The loop executes 50 times, beginning from the value of 1 till k reaches 50.

The value of k is squared and added to the variable total each time the loop executes.

total = total + (k*k);

After the square is added to total, value of variable k is incremented by 1. This new value represents the next counting number.

k++;

After 50 executions of the loop, total variable will hold the sum of the squares of all the numbers from 1 to 50. The sum is displayed at the end.

This program implements the simplest logic for calculation of sum using two variables. The other loops such as for loop and do-while loop only differ in the placement and/or evaluation of the test condition.

8 0

4 years ago

How does blockchain technology help organizations when sharing data?

Ilya [14]

Answer:

Blockchain introduces a distributed ledger that can be shared across networked devices. Individuals on the network can share files and values such as cryptocurrencies securely, on a peer-to-peer basis without the need for middlemen.

4 0

3 years ago

Solve the recurrence relation . x(n)=x(n/3)+n for n>1 ,x(1)=1

tiny-mole [99]

The solution to the recurrence relation is $x(n) = \frac 12(3n - 1)$

<h3>How to solve the relation?</h3>

The relation is given as:

x(n) = x(n/3) + n for n > 1

x(1) = 1

Calculate x(3)

x(3) = x(3/3) + 3

This gives

x(3) = x(1) + 3

x(3) = 1 + 3 = 4

Calculate x(9)

x(9) = x(9/3) + 9

This gives

x(9) = x(3) + 9

x(9) = 4 + 9 = 13

So, we have:

x(1) = 1

x(3) = 4

x(9) = 13

The above sequence forms an arithmetic sequence.

An arithmetic sequence is represented as:

x(n) = x(1) + (n - 1) * d

Substitute 9 for n

x(9) = x(1) + (9 - 1) * d

Substitute 13 for x(9) and 1 for x(1)

13 = 1 + (9 - 1) * d

This gives

12 = 8d

Divide by 8

d = 1.5

Substitute d = 1.5 in x(n) = x(1) + (n - 1) * d

x(n) = x(1) + (n - 1) * 1.5

Substitute x(1) = 1

x(n) = 1 + (n - 1) * 1.5

Expand

x(n) = 1 + 1.5n - 1.5

Evaluate the like terms

x(n) = 1.5n - 0.5

Express as fraction

x(n) = 3n/2 - 1/2

Factor out 1/2

$x(n) = \frac 12(3n - 1)$

Hence, the solution to the recurrence relation is $x(n) = \frac 12(3n - 1)$

Read more about recurrence relation at:

brainly.com/question/4082048

#SPJ1

4 0

2 years ago