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krok68 [10]
3 years ago
10

Explain the three types of periodicmaintanance. .​

Computers and Technology
1 answer:
LenaWriter [7]3 years ago
6 0

Answer:

poop i think

Explanation:

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Lorico [155]

Answer:

Ubuntu

Explanation:

Ubuntu is built on the Linux shell and is an operating system. Mac pro is a laptop model, the rest are software / websites

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A customer has a system with a Gigabyte B450 Aorus Pro motherboard. He wants to upgrade the processor from the AMD Athlon X4,950
Alenkinab [10]

Answer:

The upgrade is possible and will yield a significant increase in performance.

Explanation:

Computer systems comprises of software and hardware components. The software components of a computer are the instruction sets or programs used to control the hardware components. The hardware components are the physical parts of a computer.

The motherboard is a circuitry that connects all hardware components of the system. The CPU is the brain of the system. It must be compatible with the motherboard, else the motherboard and CPU will be damaged.

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Many people describes computers as complex machine. what can this mean?
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4 years ago
Write a string class. To avoid conflicts with other similarly named classes, we will call our version MyString. This object is d
kipiarov [429]

Answer:

Check the explanation

Explanation:

myString. h:

#include <iostream>

using namespace std;

#ifndef _MYSTRING_H_

#define _MYSTRING_H_

class myString{

private:

  char *str;

public:

  myString();

  myString(const char *s);

  void operator = (myString &s);

  int length();

  friend ostream &operator <<(ostream &out, myString &s);

  friend istream &operator >>(istream &out, myString &s);

  bool operator <(myString &s);

  bool operator <=(myString &s);

  bool operator >(myString &s);

  bool operator >=(myString &s);

  bool operator ==(myString &s);

  bool operator !=(myString &s);

};

#endif

myString. cpp:

#include "myString. h"

#include <cstring>

myString::myString(){

  str = new char;

  str[0] = '\0';

}

myString::myString(const char *s){

  int len = strlen(s);

  str = new char[len + 1];

  for(int i = 0; i < len; ++i){

      str[i] = s[i];

  }

  str[len] = '\0';

}

void myString::operator = (myString &s){

  s.str = new char[length() + 1];

  for(int i = 0; i < length(); ++i){

      s.str[i] = str[i];

  }

  s.str[length()] = '\0';

}

int myString::length(){

  return strlen(str);

}

ostream &operator <<(ostream &out, myString &s){

  out << s.str;

  return out;

}

istream &operator >>(istream &in, myString &s){

  in >> s.str;

  return in;

}

bool myString::operator < (myString &s){

  return strcmp(str, s.str) < 0;

}

bool myString::operator <= (myString &s){

  return strcmp(str, s.str) <= 0;

}

bool myString::operator > (myString &s){

  return strcmp(str, s.str) > 0;

}

bool myString::operator >= (myString &s){

  return strcmp(str, s.str) >= 0;

}

bool myString::operator == (myString &s){

  return strcmp(str, s.str) == 0;

}

bool myString::operator != (myString &s){

  return strcmp(str, s.str) != 0;

}

main. cpp:

#include "myString.h"

#include <iostream>

using namespace std;

int main(){

  myString s1, s2;

  cout << "Enter first string: ";

  cin >> s1;

  cout << "Enter second string: ";

  cin >> s2;

  cout << "you entered: " << s1 << " and " << s2 << endl;

  myString s3 = s1;

  cout << "Value of s3 is " << s3 << endl;

  if(s1 < s2){

      cout << s1 << " < " << s2 << endl;

  }

  if(s1 <= s2){

      cout << s1 << " <= " << s2 << endl;

  }

  if(s1 > s2){

      cout << s1 << " > " << s2 << endl;

  }

  if(s1 >= s2){

      cout << s1 << " >= " << s2 << endl;

  }

  if(s1 == s2){

      cout << s1 << " == " << s2 << endl;

  }

  if(s1 != s2){

      cout << s1 << " != " << s2 << endl;

  }

  return 0;

}

Kindly check the output below.

4 0
3 years ago
PLEASE TECH PEOPLE HELP ME OUT I NEED YOU -YOU GET BRAINLIEST
Wewaii [24]
It Might be "EMV". An EMV Chip, if that helps
7 0
3 years ago
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