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3 years ago

How does resonance occur when you play a horn?

2 answers:

8 0

Sound waves come from mechanical vibrations in solids, liquids, and gases. ... When a sound or light wave strikes an object, it is already vibrating at some particular frequency. If that frequency happens to match the resonant frequency of the object it's hitting, then you'll get what's called resonance.

Oliga [24]3 years ago

3 0

Answer:

When the frequency being produced by the horn matches the natural frequency of the horn then resonance occurs.

Explanation:

Every object has its own frequency called natural frequency. When the sound being produced by an instrument matches the natural frequency of the instrument then acoustic resonance is achieved. Wine glasses breaking by the application of sound is an example of this phenomenon.

So, when the frequency being produced by the horn matches the natural frequency of the horn then resonance occurs.

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igor_vitrenko [27]

Answer:

svbsshsjjsjs Hello :)

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4 years ago

Read 2 more answers

A pulley in the shape of a solid cylinder of mass 1.50 kg and radius 0.240 m is free to rotate around a horizontal shaft along t

liq [111]

Answer:

the speed of the textbook just before it hits the floor is 2.4 m/s

Explanation:

Given the data in the question;

mass of pulley = 1.50 kg

radius of pulley = 0.240 m

mass of text book = 2.0 kg

height from which text book was released = 0.9 m

angular speed of the pulley = 10.0 rad/s

the speed of the textbook just before it hits the floor = ?

the speed of the textbook v = angular speed of the pulley × radius of pulley

we substitute

v = 10.0 rad/s × 0.240 m

v = 2.4 m/s

Therefore, the speed of the textbook just before it hits the floor is 2.4 m/s

6 0

3 years ago

The lowest note on a grand piano has a frequency of 27.5 Hz. The entire string is 2.00 m long and has a mass of 440g . The vibra

ANEK [815]

Answer:

Tension, T = 2038.09 N

Explanation:

Given that,

Frequency of the lowest note on a grand piano, f = 27.5 Hz

Length of the string, l = 2 m

Mass of the string, m = 440 g = 0.44 kg

Length of the vibrating section of the string is, L = 1.75 m

The frequency of the vibrating string in terms of tension is given by :

$f=\dfrac{1}{2L}\sqrt{\dfrac{T}{\mu}}$

$\mu=\dfrac{m}{l}$

$\mu=\dfrac{0.44}{2}=0.22\ kg/m$

$T=4L^2f\mu$

$T=4\times (1.75)^2\times (27.5)^2 \times 0.22$

T = 2038.09 N

So, the tension in the string is 2038.09 N. Hence, this is the required solution.

6 0

4 years ago

Runs 4 m North and then runs 9 m West. Calculate Distance and Displacement.

mixas84 [53]

Answer:

Take north as y and west as -x.

distance=√(x^2+y^2)

displacement= tan theta(tan^-1) (y/x)

answers should be, (9.85m, 66.04°)

8 0

3 years ago

A student uses a ramp to push a box into the back of a truck. Which option describes when potential energy is converted into kin

dimulka [17.4K]

Answer:

when the student pushes the box up the ramp

Explanation:

Potential energy is energy possessed by a body by virtue of it's position.

Kinetic energy is energy possessed by a body by virtue of it's motion.

When the box is stationary, it poseses only potential energy. However, once it is being pushed up a ramp, it's potential energy is now converted into kinetic energy.

4 0

3 years ago