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Bad White [126]
3 years ago
10

Runs 4 m North and then runs 9 m West. Calculate Distance and Displacement.

Physics
1 answer:
mixas84 [53]3 years ago
8 0

Answer:

Take north as y and west as -x.

distance=√(x^2+y^2)

displacement= tan theta(tan^-1) (y/x)

answers should be, (9.85m, 66.04°)

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Which of the Jovian planets have rings?
fenix001 [56]
All of the four have rings, but if i'm not mistaken Saturn is the only visible ring.

Hope I helped, a brainleist answer would be highly appreciated! 
6 0
3 years ago
Read 2 more answers
The constant pressure molar heat capacity, C_{p,m}C p,m ​ , of nitrogen gas, N_2N 2 ​ , is 29.125\text{ J K}^{-1}\text{ mol}^{-1
antoniya [11.8K]

Answer:

Explanation:

Constant pressure molar heat capacity Cp = 29.125 J /K.mol

If Cv be constant volume molar heat capacity

Cp - Cv = R

Cv = Cp - R

= 29.125 - 8.314 J

= 20.811 J

change in internal energy = n x Cv x Δ T

n is number of moles , Cv is molar heat capacity at constant volume ,  Δ T is change in temperature

Putting the values

= 20 x 20.811 x 15

= 6243.3 J.

3 0
3 years ago
A 20-kg child is coasting at 3.3 m/s over flat ground in a 4.0-kg wagon. The child drops a 1.0-kg ball out the back of the wagon
Shalnov [3]

Answer:

The final velocity is u_f = 3.44 \  m/s

Explanation:

From the question we are told that

    The mass of the child is  m_1 = 20 \  kg

    The initial  speed  of the child is  u_1 = 3.3 \  m/s

    The mass of the wagon is  m_w =  4.0 \ kg

    The  initial  speed of the wagon is u_w = 3.3 \ m/s

    The mass of the ball is  m_2 = 1.0 \  kg

    The initial speed off the ball  is  u_2 = 3.3 \ m/s

Generally the initial  speed of the system (i.e the child , wagon ,  ball) is  

          u_1 = u_w = u_2 = u =3.3 \ m/s

Generally from the law of linear momentum conservation

    p_i = p_f

Here p_i  is the momentum of the system before the ball is dropped which is mathematically represented  as

      p_i = ( m_1 + m_2 + m_3 ) *  u

=>   p_i = ( 20  + 4 + 1 ) *  3.3

=>   p_i = 82.5 \ kg \cdot m/s

and  

       p_f  is the momentum of the system after the ball is dropped which is mathematically represented  as  

       p_f = ( m_1 + m_w ) *  u_f

=>   p_i = ( 20  + 4 ) *  u_f

So

     82.5 = 24 * u_f

=>   u_f = 3.44 \  m/s

   

4 0
3 years ago
A 4,000 kg truck is moving at +10 m/s hits a 1500 kg parked car which moves off at +10 m/s. What is the velocity of the truck
Igoryamba

Answer:

10m/s

Explanation:

Using the law of conservation of momentums

M1u1+m2u2 = (m1+m2)v

Substitute.

4000(10)+1500(10) = (4000+1500)v

40,000+15,000 = 5,500v

55000 = 5500v

v = 55000/5500

v= 10m/s

Hence the velocity of the truck after Collision is 10m/s

6 0
3 years ago
How does the electric field intensity vary with the increase of distance of the point from the centre of a charged conducting sp
Nataly_w [17]

Answer:

(i)  Electric field outside the shell:

For point r>R; draw a spherical gaussian surface of radius r.

Using gauss law, ∮E.ds=q0qend

Since E is perpendicular to gaussian surface, angle betwee E is 0.

Also E being constant, can be taken out of integral.

So, E(4πr2)=q0q

So, E=4πε01r2q

4 0
3 years ago
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