Question

What is the value of the range of the function f(x)=x²+2 for the domain value ¼?

Answer 1

Answer:

D.  For domain  x  =1/4  ,  $y = 2\frac{1}{16}$

Step-by-step explanation:

Here, the given function is $f(x) = x^2 + 2$

or we can also say that $y= x^2 + 2$

Now, for domain value of x = 1/4

$y(\frac{1}{4} ) = (\frac{1}{4} )^2 + 2 = 2 + \frac{1}{16 } = 2\frac{1}{16}$

Hence, for domain  x  =1/4  ,  $y = 2\frac{1}{16}$