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quester [9]
3 years ago
9

What are the basic tools for coding HTML manually?

Computers and Technology
2 answers:
ipn [44]3 years ago
5 0
The answer should be C, you need a text editor to write out the code, and then a web browser to view what the code creates.
statuscvo [17]3 years ago
5 0

Answer:

The correct answer is C) a text editor and web browser.

Explanation:

A text editor is important because it is the most basic and necessary tool for coding in any language, such as HTML. A web browser is important because it provides the possibility of testing the code with internet and some other tools and software the person may have uploaded. A WYSIWYG editor is not necessary for manual coding, although it may help in some cases. A monitor is actually a basic tool for all this activity because all machines must have one for visualising everything, however it is not for coding, only for visualising.

You might be interested in
Why I/O modules is needed between system bus<br>and I/O devices?​
beks73 [17]

Answer:

1. Processor communication -- this involves the following tasks:

<em>a. exchange of data between processor and I/O module</em>

<em>b. command decoding - I/O module accepts commands sent from the processor. E.g., the I/O module for a disk drive may accept the following commands from the processor: READ SECTOR, WRITE SECTOR, SEEK track, etc. </em>

<em>c. status reporting – The device must be able to report its status to the processor, e.g., disk drive busy, ready etc. Status reporting may also involve reporting various errors. </em>

<em>d. Address recognition – Each I/O device has a unique address and the I/O module must recognize this address. </em>

<em />

2. Device communication – The I/O module must be able to perform device communication such as status reporting.

3. Control & timing – The I/O module must be able to co-ordinate the flow of data between the internal resources (such as processor, memory) and external devices.

4. Data buffering – This is necessary as there is a speed mismatch between speed of data transfer between processor and memory and external devices. Data coming from the main memory are sent to an I/O module in a rapid burst. The data is buffered in the I/O module and then sent to the peripheral device at its rate.

5. Error detection – The I/O module must also be able to detect errors and report them to the processor. These errors may be mechanical errors (such as paper jam in a printer), or changes in the bit pattern of transmitted data. A common way of detecting such errors is by using parity bits.

5 0
3 years ago
In codd's model of a relational database, data is stored in a(n) _____, which maintains information about a(
Dmitry [639]
<span>Which is not a component of a database that describes how data is stored?</span>
5 0
3 years ago
The energy used by an appliance which operates at 240 volts at 15 amp for 4 hr. is A. 0.92 kwhr. B. 3.45 kwhr. C. 14.4 kwhr. D.
Tju [1.3M]

Answer:

C. 14.4 kwhr.

Explanation:

To calculate the energy used by appliance first calculate the power. The formulae for calculating power(<em>P</em>) is P= I \times V, where V stands for voltage and I stands for current.

In the given problem,  V = 240 volts and I = 15 amp. Therefore,

P=240 \times 15 =3600\ watt(w) = 3.6\ kw

Now, formulae for calculating energy used i.e. work(W) is W = P\times t, where <em>t</em> is the time.

In the given question time is 4 hr. Therefore energy used will be,

Energy used (W) = 3.6\times4 =14.4\ kwhr.

8 0
3 years ago
Using Python I need to Prompt the user to enter in a numerical score for a Math Class. The numerical score should be between 0 a
yaroslaw [1]

Answer:

<em>The program doesn't use comments; See explanation section for detailed line by line explanation</em>

<em>Program starts here</em>

def lettergrade(subject,score):

     print(subject+": "+str(score))

     if score >= 90 and score <= 100:

           print("Letter Grade: A")

     elif score >= 80 and score <= 89:

           print("Letter Grade: B")

     elif score >= 70 and score <= 79:

           print("Letter Grade: C")

     elif score >= 60 and score <= 69:

           print("Letter Grade: D")

     elif score >= 0 and score <= 59:

           print("Letter Grade: F")

     else:

           print("Invalid Score")

maths = int(input("Maths Score: "))

english = int(input("English Score: "))

pe = int(input("PE Score: "))

science = int(input("Science Score: "))

arts = int(input("Arts Score: "))

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

Explanation:

The program makes the following assumptions:

Scores between 90–100 has letter grade A

Scores between 80–89 has letter grade B

Scores between 70–79 has letter grade C

Scores between 60–69 has letter grade D

Scores between 0–69 has letter grade E

<em>Line by Line explanation</em>

This line defines the lettergrade functions; with two parameters (One for subject or class and the other for the score)

def lettergrade(subject,score):

This line prints the the score obtained by the student in a class (e.g. Maths Class)

     print(subject+": "+str(score))

The italicized determines the letter grade using if conditional statement

<em>This checks if score is between 90 and 100 (inclusive); if yes, letter grade A is printed</em>

<em>      if score >= 90 and score <= 100:</em>

<em>            print("Letter Grade: A")</em>

<em />

<em>This checks if score is between 80 and 89 (inclusive); if yes, letter grade B is printed</em>

<em>      elif score >= 80 and score <= 89:</em>

<em>            print("Letter Grade: B")</em>

<em />

<em>This checks if score is between 70 and 79 (inclusive); if yes, letter grade C is printed</em>

<em>      elif score >= 70 and score <= 79:</em>

<em>            print("Letter Grade: C")</em>

<em />

<em>This checks if score is between 60 and 69 (inclusive); if yes, letter grade D is printed</em>

<em>      elif score >= 60 and score <= 69:</em>

<em>            print("Letter Grade: D")</em>

<em />

<em>This checks if score is between 0 and 59 (inclusive); if yes, letter grade F is printed</em>

<em>      elif score >= 0 and score <= 59:</em>

<em>            print("Letter Grade: F")</em>

<em />

<em>If input score is less than 0 or greater than 100, "Invalid Score" is printed</em>

<em>      else:</em>

<em>            print("Invalid Score")</em>

This line prompts the user for score in Maths class

maths = int(input("Maths Score: "))

This line prompts the user for score in English class

english = int(input("English Score: "))

This line prompts the user for score in PE class

pe = int(input("PE Score: "))

This line prompts the user for score in Science class

science = int(input("Science Score: "))

This line prompts the user for score in Arts class

arts = int(input("Arts Score: "))

The next five statements is used to call the letter grade function for each class

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

7 0
3 years ago
Which network component connects a device with the transmission media and allows it to send?
yanalaym [24]
The wireless network I believe
5 0
3 years ago
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