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3 years ago

What are the basic tools for coding HTML manually?

2 answers:

5 0

The answer should be C, you need a text editor to write out the code, and then a web browser to view what the code creates.

statuscvo [17]3 years ago

5 0

Answer:

The correct answer is C) a text editor and web browser.

Explanation:

A text editor is important because it is the most basic and necessary tool for coding in any language, such as HTML. A web browser is important because it provides the possibility of testing the code with internet and some other tools and software the person may have uploaded. A WYSIWYG editor is not necessary for manual coding, although it may help in some cases. A monitor is actually a basic tool for all this activity because all machines must have one for visualising everything, however it is not for coding, only for visualising.

You might be interested in

Why I/O modules is needed between system bus and I/O devices?

beks73 [17]

Answer:

1. Processor communication -- this involves the following tasks:

a. exchange of data between processor and I/O module

b. command decoding - I/O module accepts commands sent from the processor. E.g., the I/O module for a disk drive may accept the following commands from the processor: READ SECTOR, WRITE SECTOR, SEEK track, etc.

c. status reporting – The device must be able to report its status to the processor, e.g., disk drive busy, ready etc. Status reporting may also involve reporting various errors.

d. Address recognition – Each I/O device has a unique address and the I/O module must recognize this address.

2. Device communication – The I/O module must be able to perform device communication such as status reporting.

3. Control & timing – The I/O module must be able to co-ordinate the flow of data between the internal resources (such as processor, memory) and external devices.

4. Data buffering – This is necessary as there is a speed mismatch between speed of data transfer between processor and memory and external devices. Data coming from the main memory are sent to an I/O module in a rapid burst. The data is buffered in the I/O module and then sent to the peripheral device at its rate.

5. Error detection – The I/O module must also be able to detect errors and report them to the processor. These errors may be mechanical errors (such as paper jam in a printer), or changes in the bit pattern of transmitted data. A common way of detecting such errors is by using parity bits.

5 0

3 years ago

In codd's model of a relational database, data is stored in a(n) _____, which maintains information about a(

Dmitry [639]

Which is not a component of a database that describes how data is stored?

5 0

3 years ago

The energy used by an appliance which operates at 240 volts at 15 amp for 4 hr. is A. 0.92 kwhr. B. 3.45 kwhr. C. 14.4 kwhr. D.

Tju [1.3M]

Answer:

C. 14.4 kwhr.

Explanation:

To calculate the energy used by appliance first calculate the power. The formulae for calculating power(P) is $P= I \times V$ , where V stands for voltage and I stands for current.

In the given problem, V = 240 volts and I = 15 amp. Therefore,

$P=240 \times 15 =3600\ watt(w) = 3.6\ kw$

Now, formulae for calculating energy used i.e. work(W) is $W = P\times t$ , where t is the time.

In the given question time is 4 hr. Therefore energy used will be,

Energy used (W) = $3.6\times4 =14.4\ kwhr$ .

8 0

3 years ago

Using Python I need to Prompt the user to enter in a numerical score for a Math Class. The numerical score should be between 0 a

yaroslaw [1]

Answer:

The program doesn't use comments; See explanation section for detailed line by line explanation

Program starts here

def lettergrade(subject,score):

print(subject+": "+str(score))

if score >= 90 and score <= 100:

print("Letter Grade: A")

elif score >= 80 and score <= 89:

print("Letter Grade: B")

elif score >= 70 and score <= 79:

print("Letter Grade: C")

elif score >= 60 and score <= 69:

print("Letter Grade: D")

elif score >= 0 and score <= 59:

print("Letter Grade: F")

else:

print("Invalid Score")

maths = int(input("Maths Score: "))

english = int(input("English Score: "))

pe = int(input("PE Score: "))

science = int(input("Science Score: "))

arts = int(input("Arts Score: "))

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

Explanation:

The program makes the following assumptions:

Scores between 90–100 has letter grade A

Scores between 80–89 has letter grade B

Scores between 70–79 has letter grade C

Scores between 60–69 has letter grade D

Scores between 0–69 has letter grade E

Line by Line explanation

This line defines the lettergrade functions; with two parameters (One for subject or class and the other for the score)

def lettergrade(subject,score):

This line prints the the score obtained by the student in a class (e.g. Maths Class)

print(subject+": "+str(score))

The italicized determines the letter grade using if conditional statement

This checks if score is between 90 and 100 (inclusive); if yes, letter grade A is printed

if score >= 90 and score <= 100:

print("Letter Grade: A")

This checks if score is between 80 and 89 (inclusive); if yes, letter grade B is printed

elif score >= 80 and score <= 89:

print("Letter Grade: B")

This checks if score is between 70 and 79 (inclusive); if yes, letter grade C is printed

elif score >= 70 and score <= 79:

print("Letter Grade: C")

This checks if score is between 60 and 69 (inclusive); if yes, letter grade D is printed

elif score >= 60 and score <= 69:

print("Letter Grade: D")

This checks if score is between 0 and 59 (inclusive); if yes, letter grade F is printed

elif score >= 0 and score <= 59:

print("Letter Grade: F")

If input score is less than 0 or greater than 100, "Invalid Score" is printed

else:

print("Invalid Score")

This line prompts the user for score in Maths class

maths = int(input("Maths Score: "))

This line prompts the user for score in English class

english = int(input("English Score: "))

This line prompts the user for score in PE class

pe = int(input("PE Score: "))

This line prompts the user for score in Science class

science = int(input("Science Score: "))

This line prompts the user for score in Arts class

arts = int(input("Arts Score: "))

The next five statements is used to call the letter grade function for each class

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

7 0

3 years ago

Which network component connects a device with the transmission media and allows it to send?

yanalaym [24]

The wireless network I believe

5 0

3 years ago