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DedPeter [7]
3 years ago
5

Write a series of conditional tests. Print a statement describing each test and your prediction for the results of each test. Fo

r example, your code may look something like this:car = 'subaru'print("Is car == 'subaru'? I predict True.")print(car == 'subaru')print("\nIs car == 'audi'? I predict False.")print(car == 'audi')Create at least 4 tests. Have at least 2 tests evaluate to True and another 2 tests evaluate to False.
Computers and Technology
1 answer:
N76 [4]3 years ago
7 0

Answer:

this:name = 'John'

print("Is name == 'John'? I predict True.")

print(name == 'John')

print("\nIs name == 'Joy'? I predict False.")

print(car == 'Joy')

this:age = '28'

print("Is age == '28'? I predict True.")

print(age == '28')

print("\nIs age == '27'? I predict False.")

print(age == '27')

this:sex = 'Male'

print("Is sex == 'Female'? I predict True.")

print(sex == 'Female')

print("\nIs sex == 'Female'? I predict False.")

print(sex == 'Joy')

this:level = 'College'

print("Is level == 'High School'? I predict True.")

print(level == 'High School')

print("\nIs level == 'College'? I predict False.")

print(age == 'College')

Conditions 1 and 2 test for name and age

Both conditions are true

Hence, true values are returned

Conditions 3 and 4 tests for sex and level

Both conditions are false

Hence, false values are returned.

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Explanation:

#include<iostream>

#include<string.h>

using namespace std;

char *removestring(char str[80])

{

   int i,j,len;

   len = strlen(str);

   for( i = 0; i < len; i++)

   {

       if (str[i] == ' ')

       {

           for (j = i; j < len; j++)

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           len--;

       }

   }

   return str;

}

int main ()

{  

char  str[80];

   cout << "Enter a string : ";

   cin.getline(str, 80);

   strcpy(removestring(str), str);

   cout << "Resultant string : " << str;

   return 0;

}

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