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iragen [17]
3 years ago
5

Which of the given original work is protected by the copyright law?

Computers and Technology
1 answer:
Mila [183]3 years ago
6 0

Answer:i would love to help but are there any answer choices?

Explanation: please provide answer choices for an accurate answer

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(Business: check ISBN-10) An ISBN-10 (International Standard Book Number) consists of 10 digits: d1d2d3d4d5d6d7d8d9d10. The last
Aneli [31]

Answer:

 The solution code is written in Python 3

  1. digits = input("Enter 9 digits: ")
  2. multiplier = 1
  3. total = 0
  4. for x in digits:
  5.    total += int(x) * multiplier  
  6.    multiplier += 1
  7. checksum = total % 11  
  8. if(checksum == 10):
  9.    print(digits + "X")
  10. else:
  11.    print(digits + str(checksum))

Explanation:

Firstly, use input function to get user input for 9 digits (Line 1)

Next we can use a for-loop to estimate the summation (d1 * 1 + d2 * 2 + d3 * 3 + d4 * 4 + d5 * 5+ d6 * 6 + d7 * 7 + d8 * 8 + d9 * 9) ( Line 6-8)

Then only apply % operator to get the remainder of total and get the checksum (Line 10)

Next create if and else statement to print the digits string joined with X if checksum is 10 else join digits string with checksum value (Line 12 -15)

7 0
3 years ago
I need help!!! i will make you a brainliest!!
Ber [7]

Answer:

What you have is correct

Explanation:

3 0
3 years ago
Two communicating devices are using a single-bit even parity check for error detection. The transmitter sends the byte 10101010
icang [17]

Answer:

The receiver will not detect the error.

Explanation:

The byte sent by transmitter: 10101010

The byte received by receiver due to channel noise: 10011010

If you see the bold part of the both sent and received bytes you can see that the number of bits changed is 2.

The two communicating devices are using a single-bit even parity check. Here there are two changed bits so this error will not be detected as this single bit even parity check scheme has a limit and it detects the error when the value of changed bit is odd but here it is even.

This parity scheme basically works well with the odd number of bit errors.

7 0
3 years ago
Question 6 options: This is a category or partitioned group of the small units of a programming language include its numeric lit
Wittaler [7]

Lexeme is a category or partitioned group of the small units of a programming language include its numeric literals, operators, and special words.

<h3>What is a lexeme in programming?</h3>

Lexemes are known to be those character strings that are put together from the character group of a program, and the token stands for what aspect of the program's grammar they are made of.

Hence, Lexeme is a category or partitioned group of the small units of a programming language include its numeric literals, operators, and special words.

Learn more about Lexeme from

brainly.com/question/14125370

#SPJ1

6 0
2 years ago
A loop should output 1 to n. If n is 5, the output is 12345. What should XXX and YYY be? Choices are in the form XXX / YYY. cin
Alona [7]

Answer:

i = 0; i < n / i + 1

Explanation:

Given that:

a loop output 1 → n

if n = 5

output = 12345

n = scnr.nextInt();

for (XXX;  i++)

{

System.out.printIn(YYY);

}

XXX / YYY is i = 0; i < n / i + 1

5 0
3 years ago
Read 2 more answers
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