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n200080 [17]
3 years ago
13

A bowl contains 25 balls numbered 1 to 25. A ball is drawn and its number is noted. Without replacing the first ball, another ba

ll is drawn.
The probability that the numbers on both balls are odd numbers is?
Mathematics
2 answers:
marta [7]3 years ago
6 0
Since the odd numbers are:

1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25


There are 13 odd numbers. From here you would multiply 25 times four to get 100 since there is 25 numbers. Then you would multiply 13, the number of odd numbers, by 4 as well and get 52. There is a 52% chance that a odd number will be picked.
wariber [46]3 years ago
6 0

Answer:

The probability that the numbers on both balls are odd numbers =\frac{13}{50}

Step-by-step explanation:

Total number of balls = 25

Total number of balls with odd numbers = 13

Probability for first ball to be odd =\frac{13}{25}

Probability for second ball to be odd without replacing the first ball =\frac{12}{24}=\frac{1}{2}

The probability that the numbers on both balls are odd numbers =\frac{13}{25}\times \frac{1}{2}=\frac{13}{50}

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Answer:

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Step-by-step explanation:

The first step is to divide 27 by 45 to get the answer in decimal form:

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avanturin [10]
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