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2 years ago

A cone has a height of 11 meters and a radius of 7 meters . What is the volume?

Mathematics

2 answers:

Levart [38]2 years ago

5 0

Answer:

564.512 m³

Step-by-step explanation:

Formula to find the volume of a cone is :

Volume = $\frac{1}{3}$ π r² h

Here,

r = radius = 7 m

h = height = 11 m

Let us solve now.

Volume = $\frac{1}{3}$ π r² h

Volume = $\frac{1}{3}$ π ×7² × 11

Volume = $\frac{1}{3}$ π × 49 × 11

Volume = $\frac{1}{3}$ π × 539

Volume = $\frac{1}{3}$ × 1693.538

Volume = 564.512 m³

Hope this helps you :-)

Let me know if you have any other questions :-)

baherus [9]2 years ago

3 0

Answer:

V = 564.2 m^3

Step-by-step explanation:

The volume of a cone is given by

V = 1/3 pi r^2 h where r is the radius and h is the height

V = 1/3 pi (7)^2 (11)

V =539 /3 * pi

Letting pi be approximated by 3.14

V = 564.1533333 m^3

Rounding to the nearest tenth

V = 564.2 m^3

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Write a trinomial whose binomial factors contain constant terms that sum to −11 and have a product of 18.

yaroslaw [1]

Answer:

The answer is (x - 9)(x - 2), or x2 - 11 + 18.

Step-by-step explanation:

Well, think about it. What two numbers add to -11 and multiply to get 18? -9 and -2 add to get -11 and multiply to get 18.

8 0

2 years ago

How many square inches are in 60 square fee

Vilka [71]

Answer:

8640 square inches

Step-by-step explanation:

There are 12 inches in one foot so there would be 12 * 12 = 144 square inches in 1 square foot. Therefore, there are 144 * 60 = 8640 square inches in 60 square feet.

8 0

3 years ago

Max's grade on the first math exam was a 94. His grade on his seond math exam was an 89. What was the percent of change in Max's

Tom [10]

We are given that

Max's grade on the first math exam was a 94

so, first exam grade =94

His grade on his seond math exam was an 89

so, second exam grade =89

change in grade=(first exam grade)-(second exam grade)

change in grade=94-89

change in grade=5

Percentage = ( change in grade)/( first exam grade) *100

so, percentage is

$=\frac{5}{94}\times 100$

so,

the percent of change in Max's grade to the nearest whole percentage was 5%..........Answer

5 0

3 years ago

Read 2 more answers

Solve for b. -11b+7 = 40−11b+7=40

Oksana_A [137]

Answer:

This equation is false

Step-by-step explanation:

Well,

-11b + 7 = 4 - 11b + 7 = 40

combine like terms

-11b + 7 = -11b + 3 = 40

Communicative property

-3 to both sides

-11b + 4 = -11b = 40

-4 to both sides

-11b = -11b = 36

+11b to both sides

0 = 36

0 is not equal to 36 meaning that this equation is false.

Thus,

the equation given is false.

Hope this helps :)

6 0

3 years ago

We have two fair three-sided dice, indexed by i = 1, 2. Each die has sides labeled 1, 2, and 3. We roll the two dice independent

Bogdan [553]

Answer:

(a) P(X = 0) = 1/3

(b) P(X = 1) = 2/9

(d) P(X = 3) = 0

(a) P(Y = 0) = 0

(b) P(Y = 1) = 1/3

Step-by-step explanation:

Given:

- Two 3-sided fair die.

- Random Variable X_1 denotes the number you get for rolling 1st die.

- Random Variable X_2 denotes the number you get for rolling 2nd die.

- Random Variable X = X_2 - X_1.

Solution:

- First we will develop a probability distribution of X such that it is defined by the difference of second and first roll of die.

- Possible outcomes of X : { - 2 , -1 , 0 ,1 , 2 }

- The corresponding probabilities for each outcome are:

( X = -2 ): { X_2 = 1 , X_1 = 3 }

P ( X = -2 ): P ( X_2 = 1 ) * P ( X_1 = 3 )

: ( 1 / 3 ) * ( 1 / 3 )

: ( 1 / 9 )

( X = -1 ): { X_2 = 1 , X_1 = 2 } + { X_2 = 2 , X_1 = 3 }

P ( X = -1 ): P ( X_2 = 1 ) * P ( X_1 = 3 ) + P ( X_2 = 2 ) * P ( X_1 = 3)

: ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )

: ( 2 / 9 )

( X = 0 ): { X_2 = 1 , X_1 = 1 } + { X_2 = 2 , X_1 = 2 } + { X_2 = 3 , X_1 = 3 }

P ( X = -1 ):P ( X_2 = 1 )*P ( X_1 = 1 )+P( X_2 = 2 )*P ( X_1 = 2)+P( X_2 = 3 )*P ( X_1 = 3)

: ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )

: ( 3 / 9 ) = ( 1 / 3 )

( X = 1 ): { X_2 = 2 , X_1 = 1 } + { X_2 = 3 , X_1 = 2 }

P ( X = 1 ): P ( X_2 = 2 ) * P ( X_1 = 1 ) + P ( X_2 = 3 ) * P ( X_1 = 2)

: ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )

: ( 2 / 9 )

( X = 2 ): { X_2 = 1 , X_1 = 3 }

P ( X = 2 ): P ( X_2 = 3 ) * P ( X_1 = 1 )

: ( 1 / 3 ) * ( 1 / 3 )

: ( 1 / 9 )

- The distribution Y = X_2,

P(Y=0) = 0

P(Y=1) = 1/3

P(Y=2) = 1/ 3

- The probability for each number of 3 sided die is same = 1 / 3.

7 0

3 years ago