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soldi70 [24.7K]
3 years ago
5

How do you solve 3x-2 divided by 8=x/4-1 ?

Mathematics
2 answers:
Nitella [24]3 years ago
7 0
(3x - 2) / (8) = (x/4) - 1

Multiply each side by 8 :

3x - 2 = 2x - 8

Add 2 to each side:

3x = 2x - 6

Subtract 2x from each side:

x = -6 .
Rasek [7]3 years ago
3 0
\frac{3x-2}{8}= \frac{x}{4-1}
<em />
\frac{3x-2}{8}= \frac{x}{3}
<em>
Cross, Multiply :
</em>

3(3x-2) = 8x

9x-6 = 8x

9x - 8x - 6 = 0

9x - 8x = 6

\boxed{x = 6}



<em><u>Note :
</u></em><em>Remember this cross multiply formula :
</em>\frac{a}{b} = \frac{c}{d} \,\,\,\,\,\,\,\,\, \to \,\,\,\,\,\,\,\,\,(a \times d) = (b \times c)

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Given:

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