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lapo4ka [179]
3 years ago
11

Is x^2y^5 simplified?

Mathematics
1 answer:
Marizza181 [45]3 years ago
6 0
Yes it is indeed nothing else can be done to this problem 
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lexi has $13.00 less that renee. together, they have a total of $95.00. how much money does renee have?
ivanzaharov [21]

Answer:

if I am right Renee would have 82.00 because Lexi has 13.00 less than Renee and together their money's adds up to 95.00 so if you take 13.00 from 95.00 you will have 82.00 that in my opinion

5 0
3 years ago
John was having a party he knows his bowl can hold 2/3 of a bag of Doritos.if he has 4 bags or Doritos how many bowls does he ne
Verizon [17]

Step-by-step explanation:

2•4 =8

8/3 =2 2/3

answer : 3

7 0
3 years ago
Pls help it for math
Morgarella [4.7K]
I think it’s 8

Hope it helps
7 0
2 years ago
Use the coordinate grid to determine the coordinates of point A:
Simora [160]

Based on the given coordinate grid, and the increment for each grid line, the coordinates of point A is ( fraction negative 1 and 1 over 4, fraction 3 over 4) or (-1¹/₄, ³/₄).

<h3>What are point A's coordinates?</h3>

The x-value of point A is said to be 5 grid lines to the left of y-axis. This means that the x value will be negative.

The increments are 1/4 so the x-value is:
= -1/4 x 5

= -1¹/₄

The y-value is given by the 3 grid lines above the x-axis which means that this value is positive:

= 1/4 x 3

= 3 /4

The coordinates of A are:

(-1¹/₄, ³/₄)

Find out more on coordinates at brainly.com/question/14355852

#SPJ1

4 0
1 year ago
Find the indicated nth partial sum of the arithmetic sequence.<br> −7, −3, 1, 5, . . ., n = 30
TiliK225 [7]

Step-by-step explanation:

Given the Arithmetic sequence

-7, -3, 1, 5, . . .

An arithmetic sequence has a constant difference d and is defined by

a_n=a_1+\left(n-1\right)d

\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n

-3-\left(-7\right)=4,\:\quad \:1-\left(-3\right)=4

\mathrm{The\:difference\:between\:all\:of\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}

d=4

\mathrm{The\:first\:element\:of\:the\:sequence\:is}

a_1=-7

as

a_n=a_1+\left(n-1\right)d

\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:

a_n=4\left(n-1\right)-7           ∵ d=4

\mathrm{Arithmetic\:sequence\:sum\:formula:}

n\left(a_1+\frac{d\left(n-1\right)}{2}\right)

\mathrm{Plug\:in\:the\:values:}

n=30,\:\space a_1=-7,\:\spaced=4

=30\left(-7+\frac{4\left(30-1\right)}{2}\right)

=30\left(58-7\right)     ∵  \frac{4\left(30-1\right)}{2}=58

=30\cdot \:51

=1530           ∵  \mathrm{Multiply\:the\:numbers:}\:30\cdot \:51=1530

Therefore, the indicated nth partial sum of the arithmetic sequence is 1530.

ANOTHER METHOD

as

a_n=4\left(n-1\right)-7

n = 30

\sum _{n=1}^{30}\:4\left(n-1\right)-7

=\sum _{n=1}^{30}4n-11

\mathrm{Apply\:the\:Sum\:Rule}:\quad \sum a_n+b_n=\sum a_n+\sum b_n

=\sum _{n=1}^{30}4n-\sum _{n=1}^{30}11

as

\sum _{n=1}^{30}4n=1860

and

\sum _{n=1}^{30}11=330

so

=1860-330

=1530

7 0
3 years ago
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