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Pepsi [2]
3 years ago
14

Provide the structure of the major product which results from 1,4-addition of br2 to the diene shown below.

Chemistry
1 answer:
Vlad1618 [11]3 years ago
7 0
The image provided shows the diene that is used for this question. We are told that the major product of the reaction is the 1,4-addition product. The result is the addition of a bromine atom to the first carbon and the fourth carbon of the diene. However, Br₂ can also add to just one alkene of the diene in a 1,2-addition to get the other product shown in the image.

As the first bromine atom adds to one of the alkenes, it adds to the first carbon which leads to the formation of a carbocation. The carbocation can be a stable tertiary center at the 2 carbon of the diene, or the less stable secondary center of the 4 carbon. To addition to the 4-carbon has a higher activation barrier which, but the product has a lower energy than the 1,2-product. Therefore, the 1,4-addition is the thermodynamic product and will form at higher temperatures. The 1,2-product is the kinetic product that will form at lower temperatures.

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When 4.979 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 16.20 grams of CO2 and 4.976 grams of H
dimaraw [331]
For Hydrocarbon combustion:

CₓHₐ + O₂ → xCO₂ + a/2 H₂O

Moles of CO₂ = 16.2 / 44 = 0.37
Moles of Carbon = 0.37
Moles of H₂O = 4.976 / 18 = 0.28
Moles of Hydrogen = 0.28 x 2 = 0.56

Molar ratio = C : H = 1 : 1.5
= 2 : 3
C₂H₃

Mass of empirical unit = 12 x 2 + 1 x 3
= 27
Mr = 54.09
Number of empirical units repeated: 54.09 / 27
= 2

Molecular formula = C₄H₆
5 0
3 years ago
The formula of the salt produced from the neutralization reaction between nitric acid and barium hydroxide is:
expeople1 [14]

Answer:

2HNO3 + Ba(OH)2 => Ba(NO3)2 + 2H2O

Explanation:

3 0
3 years ago
Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Ca2+, V5+, Br-
Jet001 [13]

Answer:

CaS, CaBr₂, VBr₅, and V₂S₅.

Explanation:

  • The ionic compound should be neutral; the overall charge of it is equal to zero.
  • Binary ionic compound is composed of two different ions.

<u>Ca²⁺ can combined with either Br⁻ or S²⁻ to form binary ionic compounds.</u>

  • CaS can be formed via combining Ca²⁺ with S²⁻ to form the neutral binary ionic compound CaS.
  • CaBr₂ can be formed via combining 1 mole of Ca²⁺ with 2 moles of Br⁻ to form the neutral binary ionic compound CaBr₂.

<u>V⁵⁺ can combined with either Br⁻ or S²⁻ to form binary ionic compounds.</u>

  • V₂S₅ can be formed via combining 2 moles of V⁵⁺ with 5 moles of S²⁻ to form the neutral binary ionic compound V₂S₅.
  • VBr₅ can be formed via combining 1 mole of V⁵⁺ with 5 moles of Br⁻ to form the neutral binary ionic compound VBr₅.

<em>So, the empirical formula of four binary ionic compounds that could be formed is: CaS, CaBr₂, VBr₅, and V₂S₅.</em>

<em></em>

5 0
3 years ago
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olga55 [171]

Answer:

Q=25.7 Kj

Explanation:

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(4.27 Mol H2O)(6.009 Kj/Mol)

Q=25.7 Kj

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