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Rzqust [24]
2 years ago
8

Which gas would effuse more slowly: Xe CO2 CH4 N2

Chemistry
1 answer:
CaHeK987 [17]2 years ago
7 0

N2 should be the gas to effuse more slowly

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If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant?
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Answer:

The correct answer is option B.

Explanation:

3NaOH+2NBr_3\rightarrow 3HOBr+3NaBr+N_2

Moles of NBr_3 = 40 mol

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According to reaction, 3 moles of NaOH reacts with 2 moles NBr_3

Then ,48 moles of NaOH will reacts with:

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As we can see that 48 moles of sodium will completey react with 32 moles of nitrogen tribromide.

Moles left after reaction = 40 mol - 32 mol = 8 mol

Hence, the NBr_3 is an excessive reagent.

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