Two major discoveries of the gold foil experiment
1 answer:
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The concentration of solution in M or mol/L can be calculated using the following formula:
.... (1)
Here, n is number of moles and V is volume of solution in L.
The molecular formula of potassium sulfate is thus, there are 2 moles of potassium in 1 mol of potassium sulfate.
1 mol of potassium will be there in 0.5 mol of potassium sulfate.
Mass of potassium is 4.15 g, molar mass is 39.1 g/mol.
Number of moles can be calculated as follows:
Here, m is mass and M is molar mass
Putting the values,
Thus, number of moles of will be
.
The volume of solution is 225 mL, converting this into L,
Thus,
Putting the values in equation (1),
Therefore, concentration of potassium sulfate solution is 0.236 M.
Answer:
Molarity of a 5.0 L solution that contains 0.5 moles of KNO3 is 0.1 M
Explanation:
Molarity : It is used to express the concentration of the solution and defined as total moles of solute present in one liter of solution .
Moles of KNO3 = 0.5 (given)
Volume of solution = 5.0 L
Substitute the value in given formula ,
on calculation,
Molarity = 0.1 mol/L
Molarity = 0.1 M
(M = mol/L)