Question 2 (1 point)<br>At the center of the atom is the electron.<br>True<br>False

Suppose we have two rock samples, A and B. If rock A was subject to both physical and chemical weathering while rock B was subje

hammer [34]

Answer:

Rock A because after physical weather and chemical weathering it more likely for Rock A to experience more chemical weathering.

Explanation: Weathering: This is a geological term used to describe the various processes and Activities involved in the breaking down of rocks either through physical,mechanical,chemical etc actions into smaller particles.

ROCK A WILL HAVE MORE CHEMICAL WEATHERING BECAUSE THE PHYSICAL WEATHERING MUST HAVE BROKEN DOWN THE PARTICLES FOR EASY WATER AND OTHER SUBSTANCE NEEDED FOR EASIER CHEMICAL REACTION OR WEATHERING.

4 0

3 years ago

Automobile airbags contain solid sodium azide, NaN3, that reacts to produce nitrogen gas when heated, thus inflating the bag. 2N

Vitek1552 [10]

Answer : The value of work done for the system is 1144.69 J

Explanation :

First we have to calculate the moles of $NaN_3$

$\text{Moles of }NaN_3=\frac{\text{Mass of }NaN_3}{\text{Molar mass of }NaN_3}$

Molar mass of $NaN_3$ = 65.01 g/mole

$\text{Moles of }NaN_3=\frac{20.2g}{65.01g/mole}=0.311mole$

Now we have to calculate the moles of nitrogen gas.

The balanced chemical reaction is,

$2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)$

From the balanced reaction we conclude that

As, 2 mole of $NaN_3$ react to give 3 mole of $N_2$

So, 0.311 moles of $NaN_3$ react to give $\frac{0.311}{2}\times 3=0.466$ moles of $N_2$

Now we have to calculate the volume of nitrogen gas.

Using ideal gas equation:

$PV=nRT$

where,

P = Pressure of $N_2$ gas = 1.00 atm

V = Volume of $N_2$ gas = ?

n = number of moles $N_2$ = 0.466 mole

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of $N_2$ gas = $22^oC=273+22=295K$

Putting values in above equation, we get:

$1.00atm\times V=0.466mole\times (0.0821L.atm/mol.K)\times 295K$

$V=11.3L$

As initially no nitrogen was present. So,

Volume expanded = Volume of nitrogen evolved

Thus,

Expansion work = Pressure × Volume

Expansion work = 1.00 atm × 11.3 L

Expansion work = 11.3 L.atm

Conversion used : (1 L.atm = 101.3 J)

Expansion work = 11.3 × 101.3 = 1144.69 J

Therefore, the value of work done for the system is 1144.69 J

5 0

3 years ago

A flame in a sealed container will go out. Explain what you know about combustion reactions to explain why.

klasskru [66]

Answer:

A combustion reaction is a reaction that involves a substance and oxygen reacts at high temperature and produces light energy and thermal energy and generate light and heat.

If a flame is in a sealed container it will go out due to the absence of oxygen to perform a combustion reaction that requires oxygen to produce heat and light. A flame is the result of a combustion reaction which also requires the oxygen to keep on burning.

3 0

3 years ago

7. How much ice is left over if 46 kJ of energy is added to 175 g of ice?

velikii [3]

Answer:

$m_{leftover}=37g$

Explanation:

Hello!

In this case, since the melting process involves the heat added to the system, the heat of fusion and the mass of water:

$Q=m\Delta H_{fus}$

Thus, as it has been reported that the heat of fusion of ice is 333.6 J/g, we can compute the melted mass of ice as shown below:

$m=\frac{Q}{\Delta H_{fus}} =\frac{46000J}{333.6J/g}\\\\m=138g$

Thus, the ice leftover results:

$m_{leftover}=175g-138g\\\\m_{leftover}=37g$

Regards!

6 0

3 years ago

Can you add different elements in a chemical equation

elena-14-01-66 [18.8K]

Answer:

No.

Explanation: You cannot change the formulas of individual substances because the chemical formula for a given substance is characteristic of that substance.

7 0

3 years ago

Question 2 (1 point)At the center of the atom is the electron.TrueFalse​

Question 2 (1 point)At the center of the atom is the electron.TrueFalse