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Vanyuwa [196]
4 years ago
5

When baking soda (NaHCO3) dissolves in water, it separates into a cation (positive ion) and an anion (negative ion). Give the ch

emical formula of each one.
Chemistry
1 answer:
goldenfox [79]4 years ago
8 0

Answer:

Na⁺ and HCO⁻₃

Explanation:

When baking soda is dissolve in water it fully ionized into positive and negative ions.

NaHCO₃  + H₂O  →  Na⁺ + HCO⁻₃

The Na⁺  than react with OH⁻ of water and produced NaOH while HCO⁻₃ react with H⁺ and produce H₂CO₃. This carbonic acid than break to produced carbon dioxide and water.

H₂CO₃ → H₂O + CO₂

Properties of baking soda:

It is odorless compound.

It is solid at room temperature.

It is used in medicine to cure the acidity of stomach.

It is used to make baking powder.

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A balloon containing N2 has 1.70 moles and occupies 3.80L. What will the volume be if the number of moles is increased to 2.60mo
leonid [27]

Answer:

5.81L

Explanation:

N1 = 1.70 moles

V1 = 3.80L

V2 = ?

N2 = 2.60 moles

Mole - volume relationship,

N1 / V1 = N2 / V2

V2 = (N2 × V1) / N1

V2 = (2.60 × 3.80) / 1.70

V2 = 9.88 / 1.70

V2 = 5.81 L

The volume of the gas is 5.81L

8 0
3 years ago
A gas mixture with a total pressure of 745 mmHg contains each of the following gases at the indicated partial pressures: CO2, 24
Setler79 [48]

<u>Answer:</u>

<u>For Part A:</u> The partial pressure of Helium is 218 mmHg.

<u>For Part B:</u> The mass of helium gas is 0.504 g.

<u>Explanation:</u>

  • <u>For Part A:</u>

We are given:

p_{CO_2}=245mmHg\\p_Ar}=119mmHg\\p_{O_2}=163mmHg\\P=745mmHg

To calculate the partial pressure of helium, we use the formula:

P=p_{CO_2}+p_{Ar}+p_{O_2}+p_{He}

Putting values in above equation, we get:

745=245+119+163+p_{He}\\p_{He}=218mmHg

Hence, the partial pressure of Helium is 218 mmHg.

  • <u>For Part B:</u>

To calculate the mass of helium gas, we use the equation given by ideal gas:

PV = nRT

or,

PV=\frac{m}{M}RT

where,

P = Pressure of helium gas = 218 mmHg

V = Volume of the helium gas = 10.2 L

m = Mass of helium gas = ? g

M = Molar mass of helium gas = 4 g/mol

R = Gas constant = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

T = Temperature of helium gas = 283 K

Putting values in above equation, we get:

218mmHg\times 10.2L=\frac{m}{4g/mol}\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 283K\\\\m=0.504g

Hence, the mass of helium gas is 0.504 g.

6 0
3 years ago
Calculate the volume of 11 g of CO2 at NTP ?​
Kitty [74]
<h3>Answer:</h3>

5.6 Liters

<h3>Explanation:</h3>
  • N.T.P. refers to the standard temperature and pressure (S.T.P).

We need to know that;

  • One mole of a gas occupies a volume of 22.4 liters at N.T.P.

In this case;

We have 11 g of CO₂

But, 1 mole of CO₂ occupies 22.4 l at N.T.P.

1 mole of CO₂ = 44 g

Therefore;

44 g of CO₂ = 22.4 liters

What about 11 g ?

= (11 g × 22.4 l)÷ 44 g

= 5.6 l

Therefore, 11 g of CO₂ will occupy a volume of 5.6 liters at N.T.P.

8 0
4 years ago
What is the percent composition by mass of oxygen in
KiRa [710]

What is the percent composition by mass of oxygen in magnesium oxide, MgO?

Answer: 39.7 percent

4 0
3 years ago
How many grams of na3po4 will be needed to produce 650. mL of a solution that has a concentration of na+ ions of 1.40 M
SashulF [63]

Answer:

I think its 1.40M Na^+ we convert to Na3PO4 which means we need 1.40M x (1 mole Na3PO4/3 mol Na^+) = 1.40 x 1/3 = 0.467 M Na3PO4.

Explanation:

7 0
4 years ago
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