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andrew-mc [135]
3 years ago
13

the legs of a right triangle have lengths of 27 meters and 36 meters. the hypotenuse has a length of 5x meters what is the value

of x
Chemistry
1 answer:
LuckyWell [14K]3 years ago
5 0
Hi there!

We can use pythagorean theorem to solve this problem here. The easiest way to go about solving this problem is to use the theorem to find the hypotenuse, then dividing it by 5 to find the value of x, since the hypotenuse is 5x.

WORK:
27^2 + 36^2 = h^2     (plugging into theorem)
729 + 1296 = h^2     (squaring the numbers)
h^2 = 2025              (adding the numbers together)
hypotenuse = 49    (taking the square root of 2025)
49/5 = x                 (dividing 49 by 5 to find x)
x = 9.8                  (dividing)

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
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How many moles of sodium atoms do you have if you have 5.60 ~
Papessa [141]

Answer:

0.93 mol

Explanation:

Given data:

Number of moles of Na atom = ?

Number of atoms = 5.60× 10²³

Solution:

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

5.60× 10²³ atoms ×  1 mol / 6.022 × 10²³ atoms

0.93 mol

3 0
3 years ago
If the half life of iridium-182 is 15 years, how much of a 3 gram sample is left after 2 half-lives?
padilas [110]

Answer:

D. 0.75 grams

Explanation:

The data given on the iridium 182 are;

The half life of the iridium 182, t_{(1/2)} = 15 years

The mass of the sample of iridium, N₀ = 3 grams

The amount left, N(t) after two half lives is given as follows;

N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}} }

For two half lives, t = 2 × t_{(1/2)}

∴ t = 2 × 15 = 30

\dfrac{t}{t_{(1/2)}} = \dfrac{30}{15} = 2

\therefore N(t) = 3 \times\left (\dfrac{1}{2} \right )^2 = 0.75

∴ The amount left, N(t) = 0.75 grams

4 0
3 years ago
What experiment did J.J thomson do?
Fittoniya [83]

Answer: C

Explanation:

7 0
3 years ago
Read 2 more answers
You have to prepare some 2 M solutions, with 10 g of solute in each. What volume of solution will you prepare, for each solute b
alexdok [17]

Answer:

             0.045 L  or 45 mL

Explanation:

Moles = Mass/M.Mass

Moles = 10 g / 109.94 g/mol

Moles = 0.09 moles

Also,

Molarity = Moles / Vol in L

Or,

Vol in L = Moles / Molarity

Vol in L = 0.09 mol / 2 mol/L

Vol in L = 0.045 L

8 0
2 years ago
After performing a dilution calculation, you determine you need 25.0 milliliters of an aqueous stock solution to make 100.0 mill
IRINA_888 [86]
A is obviously out because it leads to a volume of 125.0 milliliters of the new solution and gives you a lower concentration than you were aiming for.

D is out because you are adding 75 milliliters of the stock solution, so your concentration would be too high. You only need 25.0 milometers of stock solution per 100 milliliters of the new solution.

C is also out because it leads to 50.0 milliliters stock solution per 100 milliliters of the new solution and hence the wrong concentration.

B is by default the correct answer. It also details the correct technique. First you add the stock solution (This you know from your calculations to be 25 milliliters.) then you add the water up to the volume you needed. (Because the calculations only tell you the total volume of water not what you need to add) You also add the water last so you can rinse the neck of the flask to make sure you also get all the stock solution residue into the stock solution.

I would add the final step of stirring, but B is the only answer that can be correct.
8 0
3 years ago
Read 2 more answers
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