Suppose that the weight (in pounds) of an airplane is a linear function of the total amount of fuel (in gallons) in its tahk. Wh
1 answer:
Answer:
2002 pounds
Explanation:
To know the weight of the plane, we need to find an equation that relates the amount of fuel to the weight.
This equation can be founded using the following
Where m is the slope, x1 is the number of gallons and y1 is the respective weight. So, replacing m = 6.0, x1 = 51 gallons and y1 = 2206 pounds, we get:
Now, we can solve for y
Then, we can calculate the weight of an airplane with 17 gallons of fuel replacing x = 17 on the equation above
y = 6x + 1900
y = 6(17) + 1900
y = 102 + 1900
y = 2002
Therefore, the answer is 2002 pounds
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9514 1404 393
Answer:
D.
Step-by-step explanation:
The wording "when x is an appropriate value" is irrelevant to this question. That phrase should be ignored. (You may want to report this to your teacher.)
When you look at the answer choices, you see that all of them are negative except the last one (D). When you look at the problem fraction, you see that it is positive.
The only reasonable choice is D.
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Your calculator can check this for you.
√12/(√3 +3) ≈ 3.4641/(1.7321 +3)
= 3.4641/4.7321 ≈ 0.7321 = -1 +√3
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If you want to "rationalize the denominator", then multiply numerator and denominator by the conjugate of the denominator. The conjugate is formed by switching the sign between terms.
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<em>Additional comment</em>
We "rationalize the denominator" in this way to take advantage of the relation ...
(a -b)(a +b) = a² -b²
Using this gets rid of the irrational root in the denominator, hence "rationalizes" the denominator.
We could also have multiplied by (3 -√3)/(3 -√3). This would have made the denominator positive, instead of negative. However, I chose to use (√3 -3) so you could see that all we did was change the sign from (√3 +3).