Answer: its 18.27
Step-by-step explanation:
Answer:
- 22°F
Step-by-step explanation:
Given that :
Morning temperature = 15°F
Change in temperature = fall by 37 degree
The temperature of the end of the day:
Morning temperature + (change in temperature)
Fall by 37° = decrease in temperature by 37° = - 37°
15°F + (-37°F)
15°F - 37°F
= - 22°F
9514 1404 393
Answer:
(A) -7
Step-by-step explanation:
The function is continuous if you can draw its graph without lifting your pencil. In this case, that means each of the piecewise function definitions must have the same value at x=3.
x^2 +2 = 6x +k . . . . . must be true at x=3
3^2 +2 = 6(3) +k . . . . substitute 3 for x
9 +2 -18 = k . . . . . . . . subtract 18
k = -7 . . . . . . . simplify
Answer:
b.) 18(m+2m)
d.) 18m+18(2m)
e.) 54m
Step-by-step explanation:
Given;
total number of Mr Moretti's students = 18
number of mechanical pencils for each student = m
total number of mechanical pencils for all the students = 18m
number of regular pencils for each student = 2m
total number of regular pencils for all the students = 18(2m)
The total number of pencils given to all the 18 students by Mr Moretti is given by;
T = Total mechanical pencils + total regular pencil
T = 18m + 18(2m)
T = 18(m + 2m)
T = 18(3m)
T = 54m
Therefore, based on the expressions above, the correct options include;
b.) 18(m+2m)
d.) 18m+18(2m)
e.) 54m
Answer:
a) W₁ = 78400 [J]
b)Wt = 82320 [J]
Step-by-step explanation:
a) W = ∫ f*dl general expression for work
If we have a chain with density of 10 Kg/m, distributed weight would be
9.8 m/s² * 10 kg = mg
Total length of th chain is 40 m, and the function of y at any time is
f(y) = (40 - y ) mg where ( 40 - y ) is te length of chain to be winded
At the beggining we have to wind 40 meters y = 0 at the end of the proccess y = 40 and there is nothing to wind then:
f(y) = mg* (40 - y )
W₁ = ∫f(y) * dy ⇒ W₁ = ∫₀⁴⁰ mg* (40 - y ) dy ⇒ W₁ = mg [ ∫₀⁴⁰ 40dy - ∫₀⁴⁰ ydy
W₁ = mg [ 40*y |₀⁴⁰ - 1/2 * y² |₀⁴⁰ ⇒ W₁ = mg* [ 40*40 - 1/2 (40)² ]
W₁ = mg * [1/2] W₁ = 10*9,8* ( 800 )
W₁ = 78400 [J]
b) Now we can calculate work to do if we have a 25 block and the chain is weightless
W₂ = ∫ mg* dy ⇒ W₂ = ∫₀⁴⁰ mg*dy ⇒ W₂ = mg y |₀⁴⁰
W₂ = mg* 40 = 10*9.8* 40
W₂ = 3920 [J]
Total work
Wt = W₁ + W₂ ⇒ Wt = 78400 + 3920
Wt = 82320 [J]
