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3 years ago

What is the value of a15 if a12= 1.7 and the recursive form of a geometric sequence is an= -3an-1?

Mathematics

1 answer:

baherus [9]3 years ago

4 0

Its simple
the answer is ........

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Evaluate the integral Integral from 0 to 1 Integral from 0 to 3 Integral from 3 y to 9 StartFraction 6 cosine (x squared )Over 5

Natalka [10]

Answer:

$\int^1_0\int^3_0\int^9_{3y}\frac{6 cos x^2}{5\sqrt z}dxdydz$ $=\frac{18}{5}(1+\frac{sin2}{2})$

Step-by-step explanation:

cosine x²= cos x²

Rule

$\int x^ndx= \frac{x^{n+1}}{n+1}+c$

$\int cos \ mx \ dx = \frac{sin \ mx}{m}+c$
$\int \frac{1}{\sqrt x}dx = \frac{\sqrt x}{\frac{1}{2}} +c= 2\sqrt x+c$

Given that,

$\int^1_0\int^3_0\int^9_{3y}\frac{6 cos x^2}{5\sqrt z}dxdydz$

$=\int ^1_0[\int^3_0(\int^9_{3y} \frac{6cos x^2}{5\sqrt z}dz)dy]dz$

$=\int^1_0[\int^3_0([\frac{6cos x^2 \times \sqrt z}{5\times \frac{1}{2}}]^9_{3y})dy]dx$

$=\int^1_0[\int^3_0([\frac{12cos x^2 \times( \sqrt 9-\sqrt{3y})}{5}])dy]dx$

$=\int^1_0[\int^3_0([\frac{12cos x^2 \times( 3-\sqrt{3y})}{5}])dy]dx$

$=\int^1_0[\frac{12cos x^2 \times( 3y-\frac{\sqrt{3}y^\frac{3}{2}}{\frac{3}{2}})}{5}]^3_0dx$

$=\int^1_0[\frac{12cos x^2 \times( 3.3-\frac{2\sqrt{3}.3^\frac{3}{2}}{3})}{5}]^3_0dx$

$=\int^1_0[\frac{12cos x^2 \times( 9-6)}{5}]dx$

$=\frac{18}{5}\int^1_02cos x^2dx$

$=\frac{18}{5}\int^1_0(1+cos2x)dx$

$=\frac{18}{5}[(x+\frac{sin2x}{2})]^1_0$

$=\frac{18}{5}(1+\frac{sin2}{2})$

6 0

3 years ago

Simplify the following expression: 4-3 x 4-8.

Ivenika [448]

Answer: -3x^4-4

Step-by-step explanation: -3x^4+4-8 > =-3x^4-4

3 0

2 years ago

Solve the system by graphing!

zhannawk [14.2K]

Are you looking for where they cross ? if so its (-1,2)

6 0

3 years ago

Read 2 more answers

What is an integer between the square root of 30 and 4*Pi divided by 3

Andru [333]

$\sqrt{30}\approx5.5\\
\frac{4\pi}{3}\approx4.2$

It's 5.

3 0

3 years ago

The circle shown has a radius of 4 cm.

Vesna [10]

Answer:

8 cm

Step-by-step explanation:

4+4=8 To get the diameter, double the radius and add them together.

7 0

2 years ago