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Ira Lisetskai [31]
4 years ago
10

How many end points does a line have?

Mathematics
1 answer:
jeka57 [31]4 years ago
7 0

Answer: A line has no end points it goes on forever

though a line segment has a end point

Step-by-step explanation: pls mark brainliest

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20. It takes Zach 15 minutes to walk 7 blocks to the swimming pool. 7 At this rate, how many blocks can he walk in one minute? C
NISA [10]

Answer:

Zach chose C as the correct answer

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The equation x2 - 9 = 0 has<br> real solution(s).<br> DONE
Andru [333]

Answer:

{-3, 3}

Step-by-step explanation:

x^2 - 9 = 0 can be written in factored form as (x -3)(x + 3) = 0.  Letting each factor equal zero separately and solving for x, we get x:  {-3, 3}

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(24 oz is $3.49, 48 oz is $6.49) Figure out the unit rate for each jar of pasta sauce.
Svet_ta [14]

Answer:

Step-by-step explanation:

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3 years ago
Aubrey is 2 years less than three times Jim's age. If Aubrey is 13 how old is Jim?
34kurt

first you need to mulitply 13 x 3 which is 39, then subtract 2 which is 37.

7 0
3 years ago
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What is the sum of the first 30 terms of the arithmetic series 27,32,37,42,47
AlladinOne [14]

Answer:

2985

Step-by-step explanation:

The formula for the sum of an arithmetic series is given by the formula:

S=\frac{k}{2}(a+x_k)

Where k is the number of terms, a is the first term, and x_k is the last term. In this case, the last term is the 30th term because we are finding the sum of the first 30 terms.

So, we need to find the 30th term. To do so, we can write an explicit formula for our sequence.

The standard form for an arithmetic sequence is given by the formula:

x_n=a+d(n-1)

Where a is the initial term and d is the common difference.

From our sequence, we can see that the initial term a is 27. The common difference is 5 because each term is 5 greater than the previous one.

So, our equation is:

x_n=27+5(n-1)

So, to find the 30th term, substitute 30 for n:

x_{30}=27+5(30-1)

Subtract:

x_{30}=27+5(29)

Multiply:

x_{30}=27+145

Add:

x_{30}=172

So, the 30th term is 172.

Now, substitute this into our original sum formula:

S=\frac{k}{2}(a+x_k)

Substitute 30 for k (the amount of terms), 27 for a (the first term), and 172 for x_k (the 30th and last term). So:

S=\frac{30}{2}(27+172)

Reduce and add:

S=15(199)

Multiply:

S=2985

So, the sum of the first 30 terms is 2985.

3 0
4 years ago
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