(x-h)^2 + (y-k)^2 = r^2 where h & k are the x,y values of the center point
(x + 1)^2 + (y-3)^2 = 4^2
<span>(x + 1)^2 + (y-3)^2 = 16</span>
Answer:

Step-by-step explanation:
<u>Similar Triangles</u>
Lines ST and QR are parallel. Thus, angles S and Q are congruent, and angles T and R are congruent.
Considering the triangle PQR, the sum of its internal angles must be 180°:

Substituting the known values:

Solving for R:


Angles S and Q are congruent, thus

Angles T and R are congruent, thus

Summarizing:

Answer:
2x^2+23.
Step-by-step explanation:
Combine like terms.
This expression simplified is 2x^2+23.