We know that
<span>This problem can be represented through the following equation
</span>
A = A₀(1/2)^t/h
where
A-----------> is the amount of substance left after time t
A₀ ----------> is the original amount---------> 2 g
h-------------> is the half-life-----------> 8 days
for A=0.04 g
t=?
0.04 = 2(1/2)^t/8
0.02 = (1/2)^t/8
Take ln on both sides:
ln(0.02) = ln [(1/2)^t/8]
ln(0.02) = (t/8)(ln 1/2)
t = 8*ln(0.02)/ln(1/2)
t = 45.15 days
the answer is 45.15 days
Answer:
400/9 or 44 4/9
Step-by-step explanation:
(
25/
6
)(
32
/3
)
=
(25)(32)
(6)(3)
=
800
/18
=
400/9
Answer:
The translation is (-1, -3)
Step-by-step explanation:
Answer:
![\frac{x^2-4}{x+2} = x-2\\\frac{4x^2-1}{2x+1} = 2x-1](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2-4%7D%7Bx%2B2%7D%20%3D%20x-2%5C%5C%5Cfrac%7B4x%5E2-1%7D%7B2x%2B1%7D%20%3D%202x-1)
Step-by-step explanation:
<u>a) (x2 - 4)/(x + 2)</u>
We can simply use factorization to solve the given question.
Here the first term will be numerator and second term will be denominator.
We will factorize the numerator.
So,
![\frac{x^2-4}{x+2}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2-4%7D%7Bx%2B2%7D)
Using formula, ![a^2+b^2 = (a+b)(a-b)](https://tex.z-dn.net/?f=a%5E2%2Bb%5E2%20%3D%20%28a%2Bb%29%28a-b%29)
![\frac{x^2-4}{x+2}\\= \frac{(x^2)-(2)^2}{x+2}\\=\frac{(x+2)(x-2)}{x+2}\\= x-2](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2-4%7D%7Bx%2B2%7D%5C%5C%3D%20%5Cfrac%7B%28x%5E2%29-%282%29%5E2%7D%7Bx%2B2%7D%5C%5C%3D%5Cfrac%7B%28x%2B2%29%28x-2%29%7D%7Bx%2B2%7D%5C%5C%3D%20x-2)
<u>b) (4x2 - 1) / (2x + 1)</u>
We can simply use factorization to solve the given question.
Here the first term will be numerator and second term will be denominator.
We will factorize the numerator.
![\frac{4x^2-1}{2x+1}](https://tex.z-dn.net/?f=%5Cfrac%7B4x%5E2-1%7D%7B2x%2B1%7D)
Using formula, ![a^2+b^2 = (a+b)(a-b)](https://tex.z-dn.net/?f=a%5E2%2Bb%5E2%20%3D%20%28a%2Bb%29%28a-b%29)
![= \frac{(2x)^2-(1)^2}{2x+1}\\=\frac{(2x+1)(2x-1)}{2x+1}\\= 2x-1](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B%282x%29%5E2-%281%29%5E2%7D%7B2x%2B1%7D%5C%5C%3D%5Cfrac%7B%282x%2B1%29%282x-1%29%7D%7B2x%2B1%7D%5C%5C%3D%202x-1)
Hence,
![\frac{x^2-4}{x+2} = x-2\\\frac{4x^2-1}{2x+1} = 2x-1](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2-4%7D%7Bx%2B2%7D%20%3D%20x-2%5C%5C%5Cfrac%7B4x%5E2-1%7D%7B2x%2B1%7D%20%3D%202x-1)
Answer:
B
Step-by-step explanation:
it's B because a polynomial it's like
![a_nx^n+a_{n-1}x^{n-1}+\cdots+a_1x^1+a_0](https://tex.z-dn.net/?f=a_nx%5En%2Ba_%7Bn-1%7Dx%5E%7Bn-1%7D%2B%5Ccdots%2Ba_1x%5E1%2Ba_0)
so the only one is B