Answer:
Step-by-step explanation:
-3 = -x - 2
the equation is a bit hard to read in your questions but if that is the correct equation then the slope is -1
Complete the equation of the line through (-6,-5)(−6,−5)(, minus, 6, comma, minus, 5, )and (-4,-4)(−4,−4)(, minus, 4, comma, min
alina1380 [7]
Answer:
![y=\frac{1}{2}x-2](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B2%7Dx-2)
Step-by-step explanation:
We have been given two points on a line
and
. We are asked to write an equation passing through these points.
We will write our equation in slope-intercept form of equation
, where,
m = Slope of line,
b = Initial value or the y-intercept.
Let us find slope of given line using slope formula.
![m=\frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
Let point
and point
.
![m=\frac{-4-(-5)}{-4-(-6)}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B-4-%28-5%29%7D%7B-4-%28-6%29%7D)
![m=\frac{-4+5}{-4+6}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B-4%2B5%7D%7B-4%2B6%7D)
![m=\frac{1}{2}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B1%7D%7B2%7D)
Now, we will substitute
and coordinates of point
in slope-intercept form of equation as:
![-5=\frac{1}{2}*(-6)+b](https://tex.z-dn.net/?f=-5%3D%5Cfrac%7B1%7D%7B2%7D%2A%28-6%29%2Bb)
![-5=-3+b](https://tex.z-dn.net/?f=-5%3D-3%2Bb)
![-5+3=-3+3+b](https://tex.z-dn.net/?f=-5%2B3%3D-3%2B3%2Bb)
![-2=b](https://tex.z-dn.net/?f=-2%3Db)
Upon substituting
and
in slope-intercept form of equation, we will get our required equation as:
![y=\frac{1}{2}x-2](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B2%7Dx-2)
Therefore, our required equation would be
.
Answer:
![Ratio = 3: 2](https://tex.z-dn.net/?f=Ratio%20%3D%203%3A%202)
Step-by-step explanation:
Given
Shape: Cube
![L = 8cm](https://tex.z-dn.net/?f=L%20%3D%208cm)
The surface area is calculated as:
![Area = 6*L^2](https://tex.z-dn.net/?f=Area%20%3D%206%2AL%5E2)
![A_1 = 6*8^2](https://tex.z-dn.net/?f=A_1%20%3D%206%2A8%5E2)
![A_1 = 384](https://tex.z-dn.net/?f=A_1%20%3D%20384)
When it is cut by half; the length is affected; so, it forms a cuboid of the following dimension:
--- Length
--- Width
--- Height
The surface area is:
![Area = 2 *(L*W + H * L + W * H)](https://tex.z-dn.net/?f=Area%20%3D%202%20%2A%28L%2AW%20%2B%20H%20%2A%20L%20%2B%20W%20%2A%20H%29)
![A_2 = 2 *(4*8 + 8 *4 + 8 * 8)](https://tex.z-dn.net/?f=A_2%20%3D%202%20%2A%284%2A8%20%2B%208%20%2A4%20%2B%208%20%2A%208%29)
![A_2 = 2 *128](https://tex.z-dn.net/?f=A_2%20%3D%202%20%2A128)
![A_2 = 256](https://tex.z-dn.net/?f=A_2%20%3D%20256)
So, the ratio of surface area is:
![Ratio = A_1 : A_2](https://tex.z-dn.net/?f=Ratio%20%3D%20A_1%20%3A%20A_2)
![Ratio = 384 : 256](https://tex.z-dn.net/?f=Ratio%20%3D%20384%20%3A%20256)
Divide by 128
![Ratio = 384/128 : 256/128](https://tex.z-dn.net/?f=Ratio%20%3D%20384%2F128%20%3A%20256%2F128)
![Ratio = 3: 2](https://tex.z-dn.net/?f=Ratio%20%3D%203%3A%202)
It would be 0 because 8 is over 5 so ya
Answer:
It is not a right angled troagle
Step-by-step explanation:
Given
Sides: 5m, 7m and 9m
Required
Is it a right angled triangle?
A triangle is right angled if:
![a^2 = b^2 + c^2](https://tex.z-dn.net/?f=a%5E2%20%3D%20b%5E2%20%2B%20c%5E2)
Where a is the longest side and b,c is any of the other.
So, we have:
![9^2 = 5^2 + 7^2](https://tex.z-dn.net/?f=9%5E2%20%3D%205%5E2%20%2B%207%5E2)
![81 = 25 + 49](https://tex.z-dn.net/?f=81%20%3D%2025%20%2B%2049)
![81 \neq 74](https://tex.z-dn.net/?f=81%20%5Cneq%2074)
Since they're not equal then it is not a right angled troagle