2 years ago

Can I help someone with math

Mathematics

1 answer:

Rina8888 [55]2 years ago

8 0

Answer:

please mark my answer brainliest

Step-by-step explanation:

can you tell me a subscript n =sin to the power theta +cosec to the power n theta...and a subscript 1 =2...then prove that a subscript n =2...

You might be interested in

A tomato plant grows 24 inches tall in 10 weeks. If the rate remains the same, how tall would the plant be after 7 weeks?

joja [24]

Answer:

168 inches which is also 14 feet

3 0

2 years ago

The solution set for 7q2 − 28 = 0 is { }. (Separate the solutions with a comma) NextReset

SVETLANKA909090 [29]

7q^2 - 28 = 0

7q^2 = 28
q^2 = 4
q = +/-2
solution set is {-2,2}

6 0

2 years ago

Read 2 more answers

Solve the Differential equation (x^2 + y^2) dx + (x^2 - xy) dy = 0

natita [175]

Answer:

$\frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C$

Step-by-step explanation:

Given differential equation,

$(x^2 + y^2) dx + (x^2 - xy) dy = 0$

$\implies \frac{dy}{dx}=-\frac{x^2 + y^2}{x^2 - xy}----(1)$

Let y = vx

Differentiating with respect to x,

$\frac{dy}{dx}=v+x\frac{dv}{dx}$

From equation (1),

$v+x\frac{dv}{dx}=-\frac{x^2 + (vx)^2}{x^2 - x(vx)}$

$v+x\frac{dv}{dx}=-\frac{x^2 + v^2x^2}{x^2 - vx^2}$

$v+x\frac{dv}{dx}=-\frac{1 + v^2}{1 - v}$

$v+x\frac{dv}{dx}=\frac{1 + v^2}{v-1}$

$x\frac{dv}{dx}=\frac{1 + v^2}{v-1}-v$

$x\frac{dv}{dx}=\frac{1 + v^2-v^2+v}{v-1}$

$x\frac{dv}{dx}=\frac{v+1}{v-1}$

$\frac{v-1}{v+1}dv=\frac{1}{x}dx$

Integrating both sides,

$\int{\frac{v-1}{v+1}}dv=\int{\frac{1}{x}}dx$

$\int{\frac{v-1+1-1}{v+1}}dv=lnx + C$

$\int{1-\frac{2}{v+1}}dv=lnx + C$

$v-2ln(v+1)=lnx+C$

Now, y = vx ⇒ v = y/x

$\implies \frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C$

5 0

2 years ago

You flip a coin, spin the spinner, and flip a coin again. Find the probability of flipping heads, spinning an even number, and t

NNADVOKAT [17]

Answer:

1/10

Step-by-step explanation:

P heads,even,heads = P heads * P even *P heads =

1/2 * 2/5* 1/2 = 1*2*1/2*5*2= 1/10

7 0

2 years ago

Is anyone else trying to get help but random accounts don’t stop posting links?

kumpel [21]

Actually yeah. It’s really annoying

Maybe this bobcat will make your day better

8 0

2 years ago

Read 2 more answers