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3 years ago

Hey can y’all help me with this one

Mathematics

1 answer:

neonofarm [45]3 years ago

8 0

Answer:

um what I do is I go from like if I was doing 12 I would go 1 times 12 and then 2 times 6 and 3 times 4 and then I would stop cause it's repetitive if that makes sense

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Find the area of that with explanations thanks

TEA [102]

Answer:

900m or 300m

Step-by-step explanation:

45 x 20 = 900

30 x 10 = 300

3 0

3 years ago

Read 2 more answers

Jeffrey is scuba diving. His elevation changes by -5.5 inches every second. Jeffrey Dives for 30 seconds. What is the total chan

elena-s [515]

-165...you take -5.5 times 30 and you get -165

8 0

3 years ago

Right answer gets brainlist

sukhopar [10]

Answer:

126 square meters

Step-by-step explanation:

7 x 6 x 3. You can regroup any pair of factors to make it easier on you.

I did (7 x 6) x 3 = 42 x 3 = 126

6 0

3 years ago

Graph the quadratic function <br> F(x)=3x^2+6x-24

Oliga [24]

For this case we have the following function:
F (x) = 3x ^ 2 + 6x-24
We observe that it is a quadratic equation.
The graph is therefore a parabola.
Its cut points are:
(-4, 0)
(2, 0)
Answer:
See attached image to see graph of the function

7 0

3 years ago

A street magician asks a passerby to draw one card from a standard deck, remember it, and then replace it. The magician then shu

Romashka-Z-Leto [24]

Answer:

P( At least one of the two cards was a heart)=7/16

Step-by-step explanation:

The solution to this question can be found in two ways.

First way: Since total number of heart in a deck are four,

Probability that neither of two cards had a heart is that at both times the card drawn was not a heart, since it is an independent event, thus probability both were not heart= $\frac{3}{4}$ × $\frac{3}{4}$

= $\frac{9}{16}$

Thus, Probability that at least one of the two cards was a heart= 1- P( Neither of two cards had a heart= 1- $\frac{9}{16}$

= $\frac{7}{16}$

Second way:

Probability that first card drawn is a heart and the second one is not a heart= $\frac{1}{4}$ × $\frac{3}{4}$

= $\frac{3}{16}$

Probability that the first card drawn is not a heart and the second one is a heart= $\frac{3}{4}$ × $\frac{1}{4}$

= $\frac{3}{16}$

Probability that both cards drawn are hearts= $\frac{1}{4}$ × $\frac{1}{4}$

= $\frac{1}{16}$

Adding all these probabilities, we have the probability that at least one of the card drawn was heart= $\frac{7}{16}$

3 0

3 years ago