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Rzqust [24]
3 years ago
9

An ecology center wants to set up an experimental garden using 400 meters of fencing to enclose a rectangular area of 9900 squar

e meters. Find the dimensions of the garden. ​ (Note that the fencing will be the perimeter of the​ garden, and the formula for the perimeter of a rectangle is P​ = 2L​ + 2W.)
Physics
1 answer:
blsea [12.9K]3 years ago
6 0

Explanation:

Given that,

Fencing to be done, P = 400 m

Area of the rectangular garden, A=9900\ m^2

Let l is the length and b is the breadth of the garden. The area of the rectangle is given by :

A=l\times b

lb=9900............(1)

The perimeter of the garden is given by :

P=2(l+b)

400=2(l+b)

200=(l+b)...............(2)

On solving equation (1) and (2), we get the value of l and b are as follows :

l = 90 m and b = 110 m

or

b = 90 m and l = 110 m

So, the dimension of the garden is 90 m by 110 m. Hence, this is the required solution.

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zubka84 [21]

Responder:

A) ω = 565.56 rad / seg

B) f = 90Hz

C) 0.011111s

Explicación:

Dado que:

Velocidad = 5400 rpm (revolución por minuto)

La velocidad angular (ω) = 2πf

Donde f = frecuencia

ω = 5400 rev / minuto

1 minuto = 60 segundos

2πrad = I revolución

Por lo tanto,

ω = 5400 * (rev / min) * (1 min / 60s) * (2πrad / 1 rev)

ω = (5400 * 2πrad) / 60 s

ω = 10800πrad / 60 s

ω = 180πrad / seg

ω = 565.56 rad / seg

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Dado que :

ω = 2πf

donde f = frecuencia, ω = velocidad angular en rad / s

f = ω / 2π

f = 565.56 / 2π

f = 90.011669

f = 90 Hz

C) Periodo (T)

Recordar T = 1 / f

Por lo tanto,

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3 0
3 years ago
An electric furnace is to melt 40 kg of aluminium/hour. The initial temperature of aluminium is 32°C. Given that aluminium has s
gizmo_the_mogwai [7]

Answer:

Part a)

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Part b)

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Explanation:

Part A)

heat required to melt the aluminium is given by

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here we have

Q = 40(950)(680 - 32) + 40(450 \times 10^3)

Q = 24624 kJ + 18000 kJ

Q = 42624 kJ

Since this is the amount of aluminium per hour

so power required to melt is given by

P = \frac{Q}{t}

P = \frac{42624}{3600} kW

P = 11.84 kW

Since the efficiency is 85% so actual power required will be

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Part B)

Total energy consumed by the furnace for 30 hours

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now the total cost of energy consumption is given as

R = P \times 20 \frac{Cents}{kWh}

R = 417.9 kWh\times  20 \frac{cents}{kWh}

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3 0
3 years ago
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GalinKa [24]

Answer:

False

Explanation:

False, as a magnetic field is generated whenever current travels through a conductor.

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Answer:

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