Question

Q|C Seawater contains 3.00 mg of uranium per cubic meter. (a) Given that the average ocean depth is about 4.00 km and water covers two-thirds of the Earth's surface, estimate the amount of uranium dissolved in the ocean.

Answer 1

Seawater contains 3.00 mg of uranium per cubic meter.

Given:

The average ocean depth, $d=4km=4000m$

Water covers two-thirds of the Earth's surface

Then, the estimated amount of uranium dissolved in the ocean is $4.08 \times 10^{15}g$.

We know, that the mass per unit volume of Uranium is$m=3\times 10^{-3} g/m^{3}$.

Also, the world's energy requirement is $E_n=1.5\times10^{13} J/s$.

The radius of the earth is $x=6.371\times10^{6}$.

Calculating the amount of Uranium under the seawater is given by the expression:

$A_m= md ( \frac{2}{3} 4\pi x^{3})$

Substituting all the values in the expression, we get

$A_m=3\times 10^{-3} \times4000 ( \frac{2}{3} \times4\times\pi (6.371\times10^{6})^{3})=4.08\times 10^{15}g$.

Thus, the amount of Uranium dissolved in the ocean is $4.08 \times 10^{15}g$

To learn more about Uranium, refer to:

brainly.com/question/9099776

#SPJ4