Can someone help pls

A 20 cm long spring is attached to a wall. the spring stretches to a length of 22 cm when you pull on it with a force of 100 n.

liberstina [14]

This phenomenon can be describedby Hooke'slaw and expressed by the formula: F=k*deltax, where k is the spring's constant, and delta xis the displacement of the spring. Transposing the terms such that we want to know the value of k,

k = F/deltax = 100N/(22 cm - 20cm)
k = 50 N/cm

7 0

4 years ago

A liquid is flowing through a horizontal pipe whose radius is m. The pipe bends straight upward through a height of 10.6 m and j

zaharov [31]

Answer:

Volume flow rate $= 1.81 * 10^{-2}$ meter cube per second

Explanation:

As we know that the

Pressure at the two ends would be the same along with volume of flow.

i.e

$P_1 = P_2$

and

$A_1 V_1 = A_2 V_2$

Re arranging the file, we get -

$V_1 = \frac{A_2 V_2}{A_1}$

The flow equation is

$\frac{1}{2}\rho * V_1^2 = \frac{1}{2}\rho * V_2^2 + \rho * g * h\\$

Substituting the value of $V_1$ in above equation, we get -

$V_2 = \sqrt{\frac{2gh}{(\frac{A_2}{A_1})^2-1} }$

Substituting the given values in above equation we get

$V_2 = \sqrt{\frac{2*9.8*10.6}{(\frac{\pi 0.04^2}{\pi 0.02^2} )^2 -1} }\\ V_2 = 3.61 m$

Volume flow rate

$Q_2 = A_2 V_2\\= \pi r_2^2V_2^2\\= 3.14 * 0.04^2 * 3.61 \\= 1.81 * 10^{-2}$

7 0

3 years ago

A plastic sphere floats in water with 50.0% of its volume submerged. This same sphere floats in glycerin with 40.0% of its volum

Natasha_Volkova [10]

Explanation:

weight of water displaced=weight of sphere,

Since, plastic sphere floats in water with 50.0% of its volume submerged

so, water=2 sphere,

so sphere's density = 1/2 of water's density

Now, weight of glycerin displaced=weight of sphere,

Also given This same sphere floats in glycerin with 40.0% of its volume submerged.

so glycerin =2.5 sphere,

so sphere's density = .4 of glycerin's = 1/2 of water's.

So glycerin = 1.25 water

6 0

3 years ago

A brick is thrown upward from the top of a building at an angle of 10° to the horizontal and with an initial speed of 16 m/s. If

Basile [38]

Answer:

38.47 m

Explanation:

To find the height of the building, we will use the following equation

$y_f=y_i+v_{iy}t+\frac{1}{2}at^2$

Where yf is the final height, yi is the initial height, viy is the initial vertical velocity, t is the time, and a is the acceleration due to gravity.

If the brick is in flight for 3.1 s, we can say that when t = 3.1s, yf = 0 m. So, replacing

viy = (16 m/s)sin(10) = 2.78 m/s

a = -9.8 m/s²

we get

$0=y_i+2.78(3.1)+\frac{1}{2}(-9.8)(3.1)^2$

Solving for yi

$\begin{gathered} 0=y_i-38.48 \\ y_i=38.48\text{ m} \end{gathered}$

Therefore, the height of the building is 38.48 m

6 0

1 year ago

Your favorite team has made the playoffs, and you decide that you should host a party. Before kickoff, you turn on your wide-scr

zhuklara [117]

Answer:

5 hr

Explanation:

I just did it In my head

4 0

3 years ago