Question

How do I solve this question?

Answer 1

Hello,

we can simplify as below

$\dfrac{(2p^3q^4)^4}{(-3q^5)^2}*\dfrac{9}{(4p^2q)^2}=\dfrac{2^4p^{12}q^{16}3^2}{3^2q^{10}4^2p^4q^2}=p^{12-4}q^{16-10-2}=p^{8}q^{4}=p^{a+b}q^{b-a}$

So it means that

8 = a+b

4 = b-a

8+4 = a+b+b-a=2b

2b = 12

b = 6

and a = 6 - 4 = 2

hope this helps