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3 years ago

Quadrilateral ABCD is an isosceles trapezoid. If AB || CD, AB = m + 6, CD = 3m + 2, BC = 3m, and AD = 7m - 16, solve for m.

Mathematics

2 answers:

AleksandrR [38]3 years ago

7 0

Answer:

M= 4

Step-by-step explanation:

NARA [144]3 years ago

4 0

Answer:

C.) 4

Step-by-step explanation:

we are given ABCD is an isosceles trapezoid

AB || CD

AB = m + 6

CD = 3m + 2

BC = 3m

AD = 7m - 16

Since, ABCD is an isosceles trapezoid

so, two sides must be equal

$BC=AD$

now, we can plug values

$3m=7m-16$

now, we can solve for m

$3m-7m=7m-16-7m$

$-4m=-16$

Divide both sides by -4

and we get

$m=4$

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Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by

a_sh-v [17]

Answer:

Dimension of the box is $16.1\times 7.1\times 2.45$

The volume of the box is 280.05 in³.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the box?

Solution :

Let h be the height of the box which is the side length of a corner square.

According to question,

A sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

The length of the box is $L=21-2h$

The width of the box is $W=12-2h$

The volume of the box is $V=L\times W\times H$

$V=(21-2h)\times (12-2h)\times h$

$V=(21-2h)\times (12h-2h^2)$

$V=252h-42h^2-24h^2+4h^3$

$V=4h^3-66h^2+252h$

To maximize the volume we find derivative of volume and put it to zero.

$V'=12h^2-132h+252$

$0=12h^2-132h+252$

Solving by quadratic formula,

$h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$h=\frac{-(-132)\pm\sqrt{132^2-4(12)(252)}}{2(12)}$

$h=\frac{132\pm72.99}{24}$

$h=2.45,8.54$

Now, substitute the value of h in the volume,

$V=4h^3-66h^2+252h$

When, h=2.45

$V=4(2.45)^3-66(2.45)^2+252(2.45)$

$V\approx 280.05$

When, h=8.54

$V=4(8.54)^3-66(8.54)^2+252(8.54)$

$V\approx -170.06$

Rejecting the negative volume as it is not possible.

Therefore, The volume of the box is 280.05 in³.

The dimension of the box is

The height of the box is h=2.45

The length of the box is $L=21-2(2.45)=16.1$

The width of the box is $W=12-2(2.45)=7.1$

So, Dimension of the box is $16.1\times 7.1\times 2.45$

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emmasim [6.3K]

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timama [110]

Answer:

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Step-by-step explanation:

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shift -7x and -8 to the other side . Remember when u shift minus changes into plus.

x^2 + 7x + 8 = 0

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in quadratic equation one value comes positive and other comes in negative

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taking positive sign

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x = -7 - $\sqrt{17}$ / 2

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x = -11.12/2

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