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2 years ago

Can someone please help me

Mathematics

2 answers:

slega [8]2 years ago

5 0

I solved the iniquity for x, and your solution should be x < 2! Sorry if its not

Hunter-Best [27]2 years ago

3 0

$\text{Hi! Let's solve this problem! :)}$

In order to solve the given inequality, we should move 5 to the right, using the opposite operation.

Since the opposite of adding 5 is subtracting 5, we subtract:

x<7-5

x<2 (Answer)

Hope it helps!

Ask me if you have any doubts.

<em>Answered by</em>

<em /> $\bf{S^{i^{l^{e} n} t} }$

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Mr. Burke had 40 pencil. He gave his class 1/5 of the pencils.Then he packed away 1/4 of the pencils that reminded. All the othe

Amiraneli [1.4K]

Answer:

26 pencils were thrown away.

Step-by-step explanation:

1/5 = 8/40

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8 0

3 years ago

Subtract the following.Write your answer in standard notation. 15 - 1.3 * 10^-3

ycow [4]

Answer:

The Final Answer would be 14.9987.

Step-by-step explanation:

Given:

$15-1.3\times 10^-3$

We need to Subtract the above number.

Since the larger number is standard Notation form and smaller number is in Scientific notation form

So first we will convert the Scientific notation Number in standard Notation form we get;

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Hence The Final Answer would be 14.9987.

5 0

3 years ago

find four consecutive even integers such that the sum of the third and fourth is 6 less than four times the first

lisabon 2012 [21]

Answer:

The numbers are 2, 4, 6 and 8

Step-by-step explanation:

let the four numbers be x, y, z and l respectively

then:

x+y+z+l

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since they are all four consecutive even integers

then y=x+2

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since (z+l)–6=4x

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3 years ago

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eimsori [14]

Answer:

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(b) 3

(d) $\dfrac{1}{6}$

Step-by-step explanation:

We need simplify the given expressions.

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$(5^4)((5^2)^2)$

Using the properties of exponents we get

$(5^4)(5^4)$ $[\because (a^m)^n=a^{mn}]$

$5^{4+4}$ $[\because a^ma^n=a^{m+n}]$

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(b)

Consider the given expression is

$(9^{\frac{1}{3}})(3^{\frac{1}{3}})$

$((3^2)^{\frac{1}{3}})(3^{\frac{1}{3}})$

Using the properties of exponents we get

$(3^{\frac{2}{3}})(3^{\frac{1}{3}})$ $[\because (a^m)^n=a^{mn}]$

$3^{\frac{2}{3}+\frac{1}{3}}$ $[\because a^ma^n=a^{m+n}]$

$3^{1}$

$3$

(c)

Consider the given expression is

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$(\dfrac{3}{1})^{3}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

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(d)

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3 years ago

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Kipish [7]

Answer:

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Step-by-step explanation:

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3 years ago

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