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3 years ago

1. Define: Denominator

Mathematics

2 answers:

igomit [66]3 years ago

8 0

Answer:denominator is the lower part of a fraction.

Step-by-step explanation:

Feel pleasure to help u...

nlexa [21]3 years ago

7 0

Answer:

This is an arithmetic fraction written under the line that indicates the equal part, the divisor.

Step-by-step explanation:

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PLEASE HELP!! 20 POINTS!!

Mashcka [7]

Answer:

$12\sqrt{3}$

Step-by-step explanation:

I do not know if this is completely correct

3 0

3 years ago

The Magazine Mass Marketing Company has received 10 entries in its latest sweepstakes. They know that the probability of receivi

Serjik [45]

Answer:

P(X>4)= 0.624

Step-by-step explanation:

Given that

n = 10

p= 0.5 ,q= 1 - p = 0.5

Two fifth of 10 = 2/5 x 10 =4

It means that we have to find probability P(X>4).

P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)

We know that

$P(X=x)=(_{x}^{n})\ p^xq^{n-x}$

$P(X=0)=(_{0}^{10})\ 0.5^0\ 0.5^{10}=0.0009$

$P(X=1)=(_{1}^{10})\ 0.5^1\ 0.5^{9}=0.0097$

$P(X=2)=(_{2}^{10})\ 0.5^2\ 0.5^{8}=0.043$

$P(X=3)=(_{3}^{10})\ 0.5^3\ 0.5^{7}=0.117$

$P(X=4)=(_{4}^{10})\ 0.5^3\ 0.5^{7}=0.205$

P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)

P(X>4)= 1 -0.0009 - 0.0097 - 0.043 - 0.117-0.205

P(X>4)= 0.624

8 0

3 years ago

Read 2 more answers

Identify the graph of the equation and find (h k). x^2-2x-y^2-2y-36=0

Butoxors [25]

Answer:

c. hyperbola, (1,-1)

Step-by-step explanation:

6 0

3 years ago

Mithali buys a t.v at 12,000 and sells it at a profit of 20% how much money she gets? reduce the fraction of cp and sp to the lo

Dominik [7]

Answer:

14,400

Step-by-step explanation:

Hope this helpfull..but if it's not,im so sorry

7 0

3 years ago

A survey of 80 randomly selected companies asked them to report the annual income of their presidents. Assuming that incomes are

Artyom0805 [142]

Answer:

The 90% confidence interval estimate of the mean annual income of all company presidents is ($579,545, $590,580).

Step-by-step explanation:

The information provided is:

$n=80\\\sigma=30,000\\\bar x=585062.50\\\text{Confidence level} = 90\%$

The critical value of <em>z</em> for 90% confidence level is, 1.645.

Compute the 90% confidence interval estimate of the mean annual income of all company presidents as follows:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\\\\=585062.50\pm 1.645\times\frac{30000}{\sqrt{80}}\\\\=585062.50\pm5517.50\\\\=(579545, 590580)$

Thus, the 90% confidence interval estimate of the mean annual income of all company presidents is ($579,545, $590,580).

This interval implies that there is 90% probability that the true mean annual income of all company presidents is within this interval.

4 0

3 years ago