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makvit [3.9K]
3 years ago
13

What is the solution to the system of equations below? 2 x + 3 y = 17. 3 x + 6 y = 30. (Negative 7, 24) (3, 4) (4, 3) (24, Negat

ive 7)
PLEASE HELP 98 POINTS
Mathematics
1 answer:
uranmaximum [27]3 years ago
4 0
( x , y ) = ( 4 , 3 )
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If the length of a rectangular television screen is 20 inches and its height is 15 inches,
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Use the Pythagorean theorem: 

<span>C = √[a^2 + b^2] </span>
<span>C = √[(20^2 + 15^2] </span>
<span>C =√[400 + 225] </span>
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3 years ago
Can someone help me with this two step equation
hjlf
You have to distribute the 4 to the numbers in the parenthesese. So 4 times 3x which is 12x and 4 times 5 which is 20 so now you get 12x plus 20 equals 8. Now you have to subtract 20 from 8 which is -12 so now you have 12x=-12 now divide the 12 from x and 12 from -12 and so now you have x=-1
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Describe a sequence of transformations that maps triangle ABC onto triangle A"B"C"<br> Help please?
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the answer is reflection

7 0
4 years ago
What is the lcm of 81 and 17?​
algol [13]

Answer:

1377

Step-by-step explanation:

The least common multiple (LCM) of two or more non-zero whole numbers is the smallest whole number that is divisible by each of those numbers. In other words, the LCM is the smallest number that all of the numbers divide into evenly.

3 0
2 years ago
Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx
shutvik [7]

\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)

Let v=x+y, so that \dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}:

\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1

Now the ODE is separable, and we have

\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx

Integrating both sides gives

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx

For the integral on the left, rewrite the integrand as

\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v

Then

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C

and so

\csc v-\cot v=x+C

\csc(x+y)-\cot(x+y)=x+C

Given that y(0)=\dfrac\pi2, we find

\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1

so that the particular solution to this IVP is

\csc(x+y)-\cot(x+y)=x+1

5 0
3 years ago
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