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makvit [3.9K]
2 years ago
13

What is the solution to the system of equations below? 2 x + 3 y = 17. 3 x + 6 y = 30. (Negative 7, 24) (3, 4) (4, 3) (24, Negat

ive 7)
PLEASE HELP 98 POINTS
Mathematics
1 answer:
uranmaximum [27]2 years ago
4 0
( x , y ) = ( 4 , 3 )
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How to solve this?? (-4)-(-8)+(-4)
kirill115 [55]
(-4) - (- 8) + (- 4)
- 4 - (- 8) + (- 4)
- 4 + 8 + (- 4 )
- 4 + 8 - 4
= 0
6 0
2 years ago
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Scores on an exam follow an approximately bell shaped distribution with a mean of 76.4 and a standard deviation of 6.1 points. A
Crazy boy [7]

Answer:

b) 95%

Step-by-step explanation:

We have been given that scores on an approximately bell shaped distribution with a mean of 76.4 and a standard deviation of 6.1 points. We are asked to find the percentage of the data that is between 64.2 points and 88.6 points.

First of all, we will find z-scores of each data point as:

z=\frac{x-\mu}{\sigma}

z=\frac{64.2-76.4}{6.1}

z=\frac{-12.2}{6.1}

z=-2

Let us find z-score corresponding to normal score 88.6.

z=\frac{88.6-76.4}{6.1}

z=\frac{12.2}{6.1}

z=2

To find the percentage of the data is between 64.2 points and 88.6 points, we need to find area under a normal distribution curve that lie within two standard deviation of mean.

The empirical rule of normal distribution states that approximately 95% of data points fall within two standard deviation of mean, therefore, option 'b' is the correct choice.

6 0
3 years ago
I will give brainliest to first correct answer !! State if polygons are similar
lakkis [162]

Answer:

are similar

Step-by-step explanation:

simple

6 0
2 years ago
Read 2 more answers
Which graph represents the function f(x) = −|x − 2| − 1?
Leviafan [203]
I think it might be the 3 one and if that's not right then it would be the first one. 
3 0
3 years ago
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Find the angle between the given vectors to the nearest tenth of a degree. u = <-5, -4>, v = <-4, -3> (1 point)
sesenic [268]

Angle between u = -5i-4j , v=-4i-3j is x =0° .

<u>Step-by-step explanation:</u>

We have , two vectors u = <-5, -4>, v = <-4, -3>  or , u = -5i-4j , v=-4i-3j

We need to find angle between these two vectors . Let's find out:

We know that dot product of two vectors is defined as :

u.v =|u|(|v|)cosx , where x is angle between u & v !

⇒ u.v =|u|(|v|)cosx

⇒ cosx =\frac{u.v}{|u|(|v|)}

Now , u.v = (-5i-4j)(-4i-3j)

⇒ u.v = (-5i-4j)(-4i)-(-5i-4j)(3j)

⇒ u.v = 20+12            { i(j) = j(i) =0  }

⇒ u.v = 32

Now , Modulus of any vector  r = xi+yj is |r| = \sqrt{x^{2}+y^{2}} So ,

|u| = \sqrt{(-5)^{2}+(-4)^{2}} = \sqrt{25+16} = \sqrt{41} \\\\|v| = \sqrt{(-4)^{2}+(-3)^{2}} = \sqrt{16+9} = \sqrt{25} = 5

Putting all these values in equation cosx =\frac{u.v}{|u|(|v|)} we get:

⇒ cosx =\frac{32}{5(\sqrt{41})}

⇒ cos^{-1}(cosx) =cos^{-1}(\frac{32}{5(6.4)})

⇒ x =cos^{-1}(1)                 { cos0 = 1  }

⇒ x =0°

Therefore , Angle between u = -5i-4j , v=-4i-3j is x =0° .

8 0
3 years ago
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