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blondinia [14]
3 years ago
12

There are 3 consecutive even integers that sum to 24. What is the value of the greatest integer?

Mathematics
2 answers:
shtirl [24]3 years ago
8 0
X
x + 2
x + 4

x + x + 2 + x + 4 = 24

3x + 6 = 24

3x = 18

x = 6

6 + 4 = 10

The value of the greatest integer is 10
Hunter-Best [27]3 years ago
7 0

Answer:

10

Step-by-step explanation:

x+x+2+x+4=24

3x+6 = 24

x=6

x+4=10

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Which of the following describes the sequence 1,1,2,3,5
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A red die, a blue die, and a yellow die (all six sided) are rolled. we are interested in the probability that the number appeari
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5/54 or approximately 0.092592593  
There are 6^3 = 216 possible outcomes of rolling these 3 dice. Let's count the number of possible rolls that meet the criteria b < y < r, manually.
 r = 1 or 2 is obviously impossible. So let's look at r = 3 through 6.
 r = 3, y = 2, b = 1 is the only possibility for r=3. So n = 1
 r = 4, y = 3, b = {1,2}, so n = 1 + 2 = 3
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 r = 5, y = 4, b = {1,2,3}, so n = 4 + 3 = 7
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 And I see a pattern, for the most restrictive r, there is 1 possibility. For the next most restrictive, there's 2+1 = 3 possibilities. Then the next one is 3+2+1
= 6 possibilities. So for r = 6, there should be 4+3+2+1 = 10 possibilities.
Let's see
 r = 6, y = 5, b = {4,3,2,1}, so n = 10 + 4 = 14
 r = 6, y = 4, b = {3,2,1}, so n = 14 + 3 = 17
 r = 6, y = 3, b = {2,1}, so n = 17 + 2 = 19
 r = 6, y = 2, b = 1, so n = 19 + 1 = 20 
 And the pattern holds. So there are 20 possible rolls that meet the desired criteria out of 216 possible rolls. So 20/216 = 5/54.
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