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3 years ago

9

What is 2500g converted to kg

1 answer:

Sauron [17]3 years ago

6 0

1000 g = 1 kg
2500 g = 2,5 kg

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A model for tumor growth is given by the Gompertz equation dV dt = a (In b-, In V) V where a >0 and b >0 are constants and

Xelga [282]

Answer:

$V(t) = b^{(1-e^{-at})}$

Step-by-step explanation:

We are given the following information in the question:

$\displaystyle\frac{dV}{dt} = a (In b - In V) V$

where a > 0 and b > 0.

$\displaystyle\frac{dV}{dt} = a (In b-In V) V\\\\\displaystyle\frac{dV}{dt} = -aV(ln\frac{V}{b})\\\\\frac{dV}{V(ln\frac{V}{b})} = (-a)dt\\\\\text{Put } ln\frac{V}{b} = z\\\\\text{Integrating both sides}\\\\\int \frac{dV}{V(ln\frac{V}{b})} = \int (-a)dt\\\\\text{We get}\\\\\int \frac{dz}{z} = \int (-a)dt\\\\\\\text{where C is the constant of integration}$

$V(0) = 1~ mm^3\\V(t) = b.e^{e^{-at+C}}\\\text{Putting t =0, V(0) = 1}\\\\V(0) = 1 = b.e^{e^{C}}\\\\V(t) = b^{(1-e^{-at})}$

where v(t) is the required tumor volume as a function of time that has an initial tumor volume of V(0) = 1 cubic mm.

5 0

3 years ago

Solve for x, assuming a, b, and c are negative constants.<br><br> (ax + b)/c ≤ b

Rudik [331]

(ax + b)/c ≤ b

ax+b ≤ cb

ax ≤ cb - b

x ≤ (cb-b)/a

5 0

3 years ago

A museum sold 95 tickets for $1,025. Each adult ticket was $15, and each child ticket was $7. Let a represent the number of adul

Genrish500 [490]

Answer:

a + c = 95........eq1

15a + 7c = 1,025....eq2

Step-by-step explanation:

Given:

Total number of ticket sold = 95

Total amount collected = $1,025

Price of each adult ticket = $15

Price of each child ticket = $7

Computation:

Number of adult tickets sold = a

Number of child tickets sold = c

So,

Number of adult tickets sold + Number of child tickets sold = Total number of ticket sold

a + c = 95........eq1

and

15a + 7c = 1,025....eq2

4 0

3 years ago

How do you solve 6=3+5(y-2)

Harlamova29_29 [7]

Answer:

y= 2,75

Step-by-step explanation:

6 = 3 + 5 (y-2)

6=8(y-2)

6/8=y-2

¾=y-2

0,75+2=y

y= 2,75

4 0

3 years ago

Find the directional derivative of the function at the given point in the direction of the vector v. f(x, y, z) = xyz , (3, 3, 9

Anna [14]

The derivative of $f(x,y,z)$ in the direction of a vector $\mathbf u$ is

$\nabla_{\mathbf u}f=\nabla f\cdot\dfrac{\mathbf u}{\|\mathbf u\|}$

With $f(x,y,z)=xyz$ , we get

$\nabla f=(yz,xz,xy)$

and $\mathbf u=(-1,-2,2)$ ,

$\|\mathbf u\|=\sqrt{(-1)^2+(-2)^2+2^2}=3$

Then

$\nabla_{(-1,-2,2)}f(3,3,9)=(27,27,9)\cdot\dfrac{(-1,-2,2)}3=-21$

8 0

3 years ago